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Natasha2012 [34]
3 years ago
13

3x+2=9+2x what is x?

Mathematics
2 answers:
enyata [817]3 years ago
5 0
I think the answer is x=7
Minchanka [31]3 years ago
3 0
3x + 2 = 9 + 2x
- 2x
x + 2 = 9
- 2
x = 7

So your answer is x = 7, I hope this helps!
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The correct answer is letter E, but I am not sure how to approach this problem and I was wondering if anyone can offer any guida
Jobisdone [24]

Explanation:

The key to area in polar coordinates is the formula for the area of a sector:

  a = (1/2)r²θ

Then a differential of area* can be written as ...

  da = (1/2)r²·dθ

Filling in the given function for r, we have ...

  da = (1/2)(4cos(3θ))²·dθ = 8cos(3θ)²·dθ

The integral will have limits corresponding to the range of values of θ for one loop of the graph: -π/6 to π/6. So, the area is ...

  \displaystyle A=\int{da}=\int\limits_{-\pi /6}^{\pi /6}{8\cos{(3\theta)}^2}\, d\theta\\\\=8\int\limits_{-\pi /6}^{\pi /6}{\cos{(3\theta)}^2}

_____

* As with other approaches to finding area (horizontal or vertical slice, for example), we assume that the differential element dθ is sufficiently small that we need not concern ourselves with the fact that r is a function of θ.

6 0
3 years ago
PLEASE HELP ME!!!! I will give you 45 points Because that’s all I have!!!
Elanso [62]

Answer:

24F...........,.....

5 0
3 years ago
Complete the pairs of corresponding parts if △ABD ≅ △EFC.
vovangra [49]

Answer:

We conclude that:

∠A = ∠ FEC

Step-by-step explanation:

Given

△ABD ≅ △EFC

To determine:

∠A =

As

△ABD ≅ △EFC

So the triangles △ABD and △EFC are congruent to each other.

  • We know that congruent triangles have equal corresponding parts.

Please check the attached graph.

From the graph, it is clear that ∠A is correspondent to ∠E.

∠A = ∠E

From the attached figure, it is clear that:

∠F can also be denoted by ∠ FEC

as

∠A = ∠E

so

∠A = ∠ FEC

Therefore, we conclude that:

∠A = ∠ FEC

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Westkost [7]
I hope my answer help you in your question

8 0
3 years ago
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Choose the table that represents g(x) = 3⋅f(x) when f(x) = x − 1.
Nastasia [14]

\bf f(x)=x-1\qquad \qquad g(x)=3\cdot f(x)\implies g(x)=\underline{3(x-1)} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{ccll} x&g(x)\\ \cline{1-2} 1&0\\2&3\\3&6 \end{array}\qquad \qquad (\stackrel{x_1}{1}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{6})

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7 0
3 years ago
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