I believe the answer is indeterminate embryonic cells. Determinate cleavage or the mosaic cleavage (cell division in early embryos) is in most protostomes. It results in the developmental fate of the cells being set early in the embryo development. A cell can only be indeterminate if it has a complete set of undisturbed animal/vegetal cytoarchitectural features. It is a characteristic of deuterostomes- when the original cell in a deuterostome embryo divides, the two resulting cells can be separated and each one can individually develop into a whole organism.
Answer:
The defective Na+/K+ ATPase is not able to dephosphorylate itself.
Explanation:
Na+/K+ ATPase pump cycles between two different forms: the phosphorylated form of the Na+/K+ ATPase has a high affinity for K+ ions and low affinity for Na+ ions. The release of phosphate from ATP and phosphorylation of Na+/K+ ATPase makes the pump to release the bound 3 Na+ ions outside the cell and to bind to the 2 K+ ions from the surroundings. As the Na+/K+ ATPase is dephosphorylated, its affinity for K+ ions is reduced leading to the release of K+ inside the cell.
A defective Na+/K+ ATPase that is able to pick and bind the K+ ions but is not able to shuttle them across the membrane should be defective to achieve its dephosphorylated form. Without releasing phosphate, the affinity of the pump for K+ ions is not reduced and the pump would not be able to release them to the opposite side of the membrane.
