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3 years ago

Two Charged spheres of 6.4 nC charge are 16 cm apart. What is the magnitude of the field in middle? ( n = 10^-9, 100 cm = 1 m)

Physics

1 answer:

emmainna [20.7K]3 years ago

3 0

Answer:

zero

Explanation:

q = 6.4 nC = 6.4 x 1 0^-9 C

d = 16 cm = 0.16 m

r = 16 / 2 = 8 cm = 0.08 m

Electric field at P due to the charge placed at A

Ea = k q / r^2

Ea = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards right

Ea = 9000 Towards right

Electric field at P due to the charge placed at B

Eb = k q / r^2

Eb = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards left

Eb = 9000 Towards left

The magnitude of electric field is same but teh direction is opposite, so the resultant electric field at P is zero.

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Answer:

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Explanation:

In this exercise on simple harmonic motion we are given the expression for motion

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3 years ago

The chemical equation provided shows iron rusting to form iron oxide. Use the drop-down menu to choose the coefficients that wil

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Answer:

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$Fe + O_2 \rightarrow Fe_2 O_3$

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$4 Fe + 3 O_2 \rightarrow 2 Fe_2 O_3$

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A step index fiber has a numerical aperture of NA = 0.1. The refractive index of its cladding is 1.465. What is the largest core

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Answer:

diameter = 9.951 × $10^{-6}$ m

Explanation:

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to find out

What is the largest core diameter for which the fiber remains single-mode

solution

we know that for single mode v number is

V ≤ 2.405

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$\frac{2*\pi *r}{ wavelength} NA$ = 2.405

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3 years ago