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Trava [24]
3 years ago
5

Please provide the steps

Physics
1 answer:
elena-s [515]3 years ago
8 0

Answer:

wA - T =mA(a)

second option

Explanation:

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Strong solar winds blew dust and gas out of the solar system during which phase of the development of the Sun?
ipn [44]
The choices can be found elsewhere and as follows:

a. <span>Alpha Centauri </span>
<span>c. </span><span>T-tauri </span>
<span>b. </span><span>The Big Bang </span>
<span>d. </span><span>Nebular
</span>
I believe the correct answer from the choices listed above is option D. <span>Strong solar winds blew dust and gas out of the solar system during Nebular phase. This seems to be the most logical option from the choices. Hope this helps. Have a nice day.</span>
8 0
2 years ago
Read 2 more answers
Give reasons.<br>A stone thrown upward returns back to the earth surface.​
Wittaler [7]

Answer:

Gravity

Explanation:

Due to earths gravity, anything that goes into the air returns back to the surface unless it is given the ability to fly.

Hope this helps!

7 0
3 years ago
Physics help please!
Oliga [24]

Answer:

student attach a save block to a horizontal spring so that the block spring system will oscillator with the block spring system released from rest horizontal position that is not the systems equilibrium position well this question regards about the energy used the answer may be 0.73 Joel ok you just try it ok verified

Explanation:

apply applied the potential energy value mean the formula MGH write it means what mass into gravitation in to height

6 0
3 years ago
The work-energy theorem states that the work done on an object is equal to a change in which quantity?
Fynjy0 [20]

The work-energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

8 0
2 years ago
A machine runs for 50 seconds with a steady power output of 100 watts. How many joules of work does the
liberstina [14]

Answer:

The answer to your question is when time = 50 s, work = 5000 J

                                                    when time = 90 s, work = 9000 J

Explanation:

Data

time = 50 s or 90 s

Power = 100 watts

Power is defined as the rate of work done per unit of time.

           Power = Work / time

-Solve for Work

           Work = Power x time

-Substitution

           Work = 100 x 50

-Result

           Work = 5000

2.-When time = 90 s

           Work = 100 x 90

-Result

          Work = 9000 watts

6 0
2 years ago
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