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Serhud [2]
3 years ago
12

A 4-kilogram cat is resting on top of a bookshelf that is 3 meters high. What is the cat’s gravitational potential energy relati

ve to the floor if the acceleration due to gravity is 9.8 m/s^2?
Physics
1 answer:
hichkok12 [17]3 years ago
4 0
The answer is 117.6 J

The potential energy of the object is actually its stored energy:

<span>E = m · g · h
E - the potential energy of the object,
m - the mass of the object,
g - acceleration due to gravity,
h - the height of the object.

m = 4 kg
g = 9.8 m/s</span>²
h = 3 m

E = 4 * 9.8 * 3 = 117.6 J
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weqwewe [10]

Answer:

a)t=1.4\times 10^{-5}\ s

b)S= 46.4 cm

Explanation:

Given that

Velocity = 16 Km/s

V= 16,000 m/s

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E=0.027 V/m

d= 22.5 cm

d= 0.225 m

a)

lets time taken by electron is t

d = V x t

0.225 = 16,000 t

t=1.4\times 10^{-5}\ s

b)

We know that

F = m a = E q                    ------------1

Mass of electron ,m

m=9.1\times 10^{-31}\ kg

Charge on electron

q=1.6\times 10^{-19}\ C

So now by putting the values in equation 1

a=\dfrac{E q}{m}

a=\dfrac{1.6\times 10^{-19}\times 0.027}{9.1\times 10^{-31}}\ m/s^2

a=4.74\times 10^{9}\ m/s^2

S= ut+\dfrac{1}{2}at^2

Here initial velocity u= 0 m/s

S= \dfrac{1}{2}\times 4.74\times 10^{9}\times (1.4\times 10^{-5})^2\ m

S=0.464 m

S= 46.4 cm

S is the deflection of electron.

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True because the picture below proves this....

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<em>∞ 234483279c20∞</em>

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