KE=1/2mv^2
KE=1/2 x 5kg x (10m/s)^2
KE= 2.5kg x 100m^2/s^2
KE= 250 J
Answer:
work output is always less than work input - the ratio is less than 1.
Explanation:
This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).
In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.
Regarding the ratio work output to work input:
because work input WI is always greater than work output WO.
Answer: fluorine
Explanation:
They are both halogens (group XVIII).
Explanation:
<u>Using equations of motion</u> :
(A) we know that,
u = 0
a = 3.7 m/s^2
S = 63
(B)
v = u + at
21.6 = 0 + 3.7 * t
<u>t (time to reach 63 m) = 5.83 seconds</u>
Answer:
13.02 m/s the velocity and 86.92 degrees the direction relative to ground
Explanation:
We need to add velocities in vector addition to find the resultant velocity "" of the balloon (the 13 m/s and the 0.7 m/s).
The velocities are at 90 degrees from each other (one pointing up and the other to the East). Notice from the attached image that the resultant velocity vector (picture in red) is actually the hypotenuse of a right angle triangle.
So we use Pythagoras to find the length (magnitude) of the resultant velocity vector:
we can round the answer to 13.02 m/s
Now we need to find the angle that this new vector makes with the ground by using the definition of tangent of an angle that relates the two quantities that we just added:
So we round it to 86.92 degrees