<span>△ABC∼△DEF
</span>Height of <span>△ABC: h1=20 inches
</span>Height of △DEF: h2=24 inches
<span>Ratio of the area of △ABC to the area of △DEF: R=?
</span>
R=(h1/h2)^2
R=[ (20 inches) /(24 inches) ]^2
R=(5/6)^2
R=5^2/6^2
R=25/36
Answer: T<span>he ratio of the area of △ABC to the area of △DEF is 25/36</span>
Answer:
400cm^2
Step-by-step explanation:
For this question, you need to find the surface areas of both objects, then add them together.
For the cube:
56cm for the front
56cm for the back
42cm for the side
42cm for the other side
48cm for the top
48cm for the bottom
SA for the cube: 292cm^2
For the triangle, things are a little different. We do the same process that we did to find the SA of the cube, but we do not have to find the SA of the top side (because there isn't a top side) and we have to divide the total SA by 2 because it's a triangle.
For the triangle:
42cm for the front
42cm for the back
54cm for the slanted side
42cm for the other side
36cm for the bottom
SA for the triangle: (216/2)^2=108cm^2
292+108=400cm^2
the SA of the composite figure is 400cm^2
Answer:
21
Step-by-step explanation:
Remember that the centroid splits the 3 medians of a triangle into a ratio of 1:2
Since TS < TN, TS = 42/2 = 21
Download photo math, it helps quicker! step by step.
Answer:
Your answer is 1500 foot pounds.
I hope this helps!
Step-by-step explanation:
Edg 2020
