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exis [7]
3 years ago
14

When a pendulum is at the position all the way to the left when it is swinging (at the top of the arc), what is true of the kine

tic and potential energy?
Physics
1 answer:
sveticcg [70]3 years ago
6 0
Kinetic energy is greatest when it passes through the center, lowest point. Potential energy is zero there.
Potential energy is greatest at the left and right ends, where it stops and heads back the other way. Kinetic energy is zero there.
So the pendulum is constantly converting its energy from one state to the other.
Pull it to the side and hold. Energy is all potential. Then let it go.
One complete swing ... to the other side and back to your hand ... does this:
Potential & let it go -> kinetic -> potential -> kinetic -> Potential & catch it.
<span>. . . . . . . . . . . . . . . . . . center . . . . . . . . . . . . center this is sombody elses but i moved here for you


still mark brainlest please if right

</span>
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An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to
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We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
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8 0
3 years ago
An ideal gas is compressed at constant pressure p=1500 Pa from a volume Vi=0.4 m3 to Vf=0.25 m3. At the same time, heat is trans
Anon25 [30]

To solve this problem we will apply the first law of thermodynamics and we will make a balance between the heat transferred, its internal energy and the total work. Recall that for gases the definition of work can be expressed in terms of its pressure and volume. Let's start

dQ = dU +dW

Here,

dU = Internal Energy

dW = Work

But internal energy is unchanged, then

dQ = dW

dQ = PdV

Where

dV= Change in Volume

P = Pressure

Finally, the expression of the heat transferred can be expressed in terms of pressure and volume, so it would end up becoming

dQ = p(v_i-v_f)

Replacing,

dQ = (1500)(0.4-0.25)

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Therefore the correct answer is B.

3 0
4 years ago
A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9
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Answer:

C = 46.891 \mu F

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

s = \frac{P}{P.F} < COS^{-1} 0.65

S = \frac{1250}{0.65} < 49.45

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]

solving for Q_{new}

Q_{new} = P tan [cos^{-1} P.F new]

Q_{new} = 1250 [tan[cos^{-1}0.9]]

Q_{new} = 605.40 VARS

Q_C = Q - Q_{new}

Q_C = 1461 - 605.4 = 855.6 vars

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C = \frac{Q_C}{ v_{rms}^2 \omega}

C = \frac{855.6}{220^2 \times 2\pi \times 60}

C = 4..689 \times 10^{-5} Faraday

C = 46.891 \mu F

6 0
4 years ago
what is formed when two or more substances are so evenly mixed that you can't see the different parts
Andre45 [30]
A homogenous mixture
5 0
4 years ago
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