1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Wewaii [24]
3 years ago
6

A supertrain with a proper length of 100 m travels at a speed of 0.950c as it passes through a tunnel having a proper length of

50.0 m. As seen by a trackside observer, is the train ever completely within the tunnel? If so, by how much do the train’s ends clear the ends of the tunnel?
Physics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

19m

Explanation:

we have proper length L = 100m

the speed of the train v = 0.95

the speed of light is given as = 3x10⁸

length of the tunnel is given as = 50 meters

we can solve for the lenght contraction as

LX√1-v²/c²

= 100 * √1-(0.95*3x10⁸)²/(3x10⁸ )

= 31.22 metres

the train would be well seen at

50 - 31.22

= 18.78

= this is approximately 19 metres

we conclude tht the trains ends clears the ends of the tunnel by 19 meters.

thank you!

You might be interested in
Help, please
Mice21 [21]

Answer:

A and A

Explanation:

see paper for work! :)

8 0
3 years ago
In science, a hypothesis must be true.
Anon25 [30]
I would believe that this is false.
6 0
4 years ago
A motor-driven winch pulls a 50.0 kg student 5.00 m up the rope at a constant speed of 1.25 m/s. how much power does the motor u
nadya68 [22]
Power is the rate work done given by dividing work done by unit time. It is measured in watts equivalent to J/s.
In this case the force by the student is mg = 490 N (taking g as 9.8m/s²)
Work done is given by force × distance,
Therefore, Power =(force × distance)/ time, but velocity/speed =distance/time
Thus, Power = force × speed/velocity
                     = 490 N × 1.25
                     = 612.5 J/S (Watts)
Hence, power will be 612.5 Watts.
7 0
4 years ago
If you go twice as fast, your kinetic energy becomes.
xenn [34]

Answer:

2 times bigger

Explanation:

hope this helps if so, please vote and mark as Brainlist! thanks and good luck!

5 0
3 years ago
Read 2 more answers
What is the surface temperature of Sirius B in Kelvins?
Sauron [17]

Answer: The surface temperature of Sirius B is 25,200 Kelvins(K).

Explanation: You would think Sirius would have a surface temperature of 9,940 Fahrenheit. That is somewhat correct, but Sirius is a binary star consisting of a main-sequence star of spectral type A0 or A1, termed Sirius A, and a faint white dwarf companion of spectral type DA2, termed Sirius B. Sirius, Sirius A, and Sirius B, are all different stars. Sirius A has a temperature of 9,940 Kelvins, but Sirius B has a temperature of 25,200 Kelvins(K).

7 0
2 years ago
Read 2 more answers
Other questions:
  • Does a physical change affect the identity of a substance? Does a chemical change affect the identity of a substance?
    5·1 answer
  • An fm radio station broadcasts at a frequency of 101.3 mhz. what is the wavelength?
    12·2 answers
  • A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in
    14·1 answer
  • Air at 25°C and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible
    13·1 answer
  • This direct relationship graph shows that the position of the car as time elapses.
    9·1 answer
  • How was the speed of light determined
    14·2 answers
  • Derive an expression for the energy needed to launch an object from the surface of Earth to a height h above the surface.Ignorin
    9·1 answer
  • Plz answer fast the question
    8·1 answer
  • A 2 kg toy car moves at a speed of 5 m/s.<br> What is the kinetic energy of the car?
    8·1 answer
  • The students on the right are applying a force of 100 N to the right. This is shown by the red arrow. The students on the left a
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!