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Wewaii [24]
2 years ago
6

A supertrain with a proper length of 100 m travels at a speed of 0.950c as it passes through a tunnel having a proper length of

50.0 m. As seen by a trackside observer, is the train ever completely within the tunnel? If so, by how much do the train’s ends clear the ends of the tunnel?
Physics
1 answer:
Nana76 [90]2 years ago
8 0

Answer:

19m

Explanation:

we have proper length L = 100m

the speed of the train v = 0.95

the speed of light is given as = 3x10⁸

length of the tunnel is given as = 50 meters

we can solve for the lenght contraction as

LX√1-v²/c²

= 100 * √1-(0.95*3x10⁸)²/(3x10⁸ )

= 31.22 metres

the train would be well seen at

50 - 31.22

= 18.78

= this is approximately 19 metres

we conclude tht the trains ends clears the ends of the tunnel by 19 meters.

thank you!

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Answer:

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Explanation:

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               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

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hope it helps.

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