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Wewaii [24]
3 years ago
6

A supertrain with a proper length of 100 m travels at a speed of 0.950c as it passes through a tunnel having a proper length of

50.0 m. As seen by a trackside observer, is the train ever completely within the tunnel? If so, by how much do the train’s ends clear the ends of the tunnel?
Physics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

19m

Explanation:

we have proper length L = 100m

the speed of the train v = 0.95

the speed of light is given as = 3x10⁸

length of the tunnel is given as = 50 meters

we can solve for the lenght contraction as

LX√1-v²/c²

= 100 * √1-(0.95*3x10⁸)²/(3x10⁸ )

= 31.22 metres

the train would be well seen at

50 - 31.22

= 18.78

= this is approximately 19 metres

we conclude tht the trains ends clears the ends of the tunnel by 19 meters.

thank you!

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Answer:

5\cdot 10^{-9} F

Explanation:

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In this problem, we have

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Substituting into the equation, we find

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A horizontal spring required a force of 1.0 N to compress it 0.1 m. How much work is required to stretch the spring 0.4 m?
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<h2>0.5J</h2>

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