As per above given data
initial velocity = 19.3 km/s
final velocity = - 18.8 km/s
now in order to find the change in velocity




Part b)
Now we need to find acceleration
acceleration is given by formula

given that


now the acceleration is given as


so above is the acceleration
Answer:
58.44 C
Explanation:
Electric field is found by
Therefore, the charge is


Therefore, required charge is 58.44 C
Answer:
Linear motion is a one-dimensional motion along a straight line, and can therefore be described mathematically using only one spatial dimension.
Explanation:
Answer:
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Explanation:
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