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Sphinxa [80]
3 years ago
5

Why doesn't the moon turn black during a total lunar eclipse? Explain your answer​

Physics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

Thank me mark me brainliest

Explanation:

I did not explain because i got a photo

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Does centripetal force change in uniform circular motion?
HACTEHA [7]
It depends on how fast you are going and in orincipal no
7 0
4 years ago
In your physics lab you are given a 10.1-kg uniform rectangular plate with edge lengths 68.7 cm by 47.5 cm. Your lab instructor
VladimirAG [237]

Answer:

2.35 kgm^2

Explanation:

we take length 68.7 cm as x-axis and 47.5 cm as y-axis then the axis about which we have to find out moment of inertia will be z-axis.

moment of inertia about x-axis

I_x = ML^2 /3 = 10.1\times 0.4752 /3 = 0.7596 kg-m2

I_y = 10.1\times 0.6872 / 3 = 1.5889 kgm^2

by perpendicular axis theorem

I_z = I_x + I_y = 0.7596 + 1.5889 = 2.35 kgm^2

4 0
3 years ago
mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
3 years ago
Consider the third period of the periodic table. Which element has the smallest atomic radius?
Anettt [7]
According to periodic trends in the periodic table, the atomic radius decreases from left to right. 

In period three, the element with the smallest atomic radius would be the element in the rightmost area. Protons increase as it goes to the right, which would mean they pull in electrons closer which decreases the size. 

So in period 3, the element with the smallest atomic radius is Argon (Ar). 
3 0
4 years ago
very dense * powerful gravitational field * extremely compact space object * spectroscope data reveal swirling gas Observations
pickupchik [31]
All of the observations except "powerful gravitational field" are consistent with the current theory of black holes.

The gavitational field of a black hole is thought to be no different than that of an ordinary star with the same mass.
5 0
3 years ago
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