Left. Opposite of the direction the box is pushed.
Explanation:
Initial velocity is 25m/s i.e. u. Final velocity would be zero since the bus stopped. It is noted that the bus deccelartion of 4m/s, so the acceleration should be considered negative of 4m/s I.e. 4m/s. So using third law of motion i.e.
v^2 - u^2= 2as
(0)^2 - (25)^2= -2×4×s {Note here I used minus sign in acceleration}
-625 = -8×s
s=625 ÷ 8
s= 125 m
So bus would cover a distance of 125m before coming to rest.
Not sure if this answer is write or wrong but i think its <span>4500 watts
</span>
Answer:
<h2><u>Constant</u></h2>
Explanation:
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<h2>Thanks</h2>
