All categories

3 years ago

write the equation of a line in point slope form through (-3,2) and parallel to a line with a slope of 5

1 answer:

3 0

Parallel lines have the same slope, so the slope is 5
in point=slope form: (y-2)=5[(x-(-3)]
y-2=5(x+3)

in slope intercept form: y=5x+17
in standard form: 5x-y=-17

You might be interested in

An aircraft flew 5 hours with the wind. The return trip took 6 hours against the wind. If the speed of the plane in still air is

Yakvenalex [24]

Answer:

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

Step-by-step explanation:

Given:

Time taken with wind = 5 hour

Time taken against wind = 6 hour

Assume;

Speed of wind = s

So,

Speed of Plane with wind = (260 + s) miles per hour

Speed of Plane against wind = (260 - s) miles per hour

Distance = speed x time

So,

(260 + s)5 = (260 - s)6

1,300 + 5s = 1,560 - 6s

11s = 260

s = 23.63 miles per hour

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

5 0

2 years ago

Help me please with this math question! giving brainliest to the correct answer

Arlecino [84]

Answer:

12.5

Step-by-step explanation:

All I really did was divide the circumference by pi to get the diameter which you end up dividing it by two to get the radius.

8 0

2 years ago

Read 2 more answers

Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.

Yakvenalex [24]

The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as

v+ = 2.29 1mile/hour

<h3>What is the rate Evelyn and Meredith were paddling?</h3>

Generally, the equation for the up and downstream motion is mathematically given as

vup=v-2

vdown=v+2

Therefore, Statement interpretation

2/3=40*1/60

3+2/3hr=11/3

Where, tup+tdown=11/3

tup+tdown=11/3

1/Vup+1/vdown=11/3

Considering the LCD equation

3(v-2)(V+2)

Hence

$\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}\\\\3(v+2)+3(v-2)=11(v+2)(v-2)$

11v^2-6v-44=0

$v=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Resolving using the equation we have

v+ = 2.29 1mile/hour

v- = -1.745 mile hour