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Dmitry [639]
3 years ago
10

Water can be used to create electricity. this type of energy is called _____. nuclear power hydroelectric power electrolysis cur

rents
Physics
1 answer:
ioda3 years ago
8 0
Hydroelectric power. That's just the term for electricity gained by using water, think of a water mill.
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A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A
ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is m  =  1612.5  \  kg

Explanation:

From the question we are told that

   The radius of the grinding wheel is R =  0.330 \ m

   The  tangential force is F_t =  250 \ N

    The angular acceleration is  \alpha  =  0.940 \ rad/s^2

The torque experienced by the wheel is mathematically represented as

     \tau  =  I  *  \alpha

Where  I  is the moment of inertia

The torque experienced by the wheel can also be  mathematically represented as

       \tau  =  F_t  * r

substituting values

       \tau  =  250 * 0.330

      \tau  = 82.5  \ N\cdot m

So

   82.5  =  I *  \alpha

    82.5  =  I *  0.940

So

   I  =  87.8 \ kg \cdot m^2

This moment of inertia can be mathematically evaluated as

     I  =  \frac{1}{2} * m* r^2

substituting values

  87.8  =  \frac{1}{2} * m* (0.330)^2

=>   m  =  1612.5  \  kg

5 0
3 years ago
It takes _______ days of combined heat exposure and exercise for your body to adapt to the heat.
lora16 [44]
D is the answer because your body can do that in all the 7 location where the heat goes in your body in 2,3, OR 5-6 days 
7 0
3 years ago
Read 2 more answers
Case 1: A DJ starts up her phonograph player. The turntable accelerates uniformly from rest, and takes t₁ = 11.9 seconds to get
olga_2 [115]

Answer:

Part a)

\omega = 8.17 rad/s

Part b)

N = 7.74 rev

Part c)

\alpha = 0.69 rad/s^2

Part d)

\alpha = 0.48 rad/s^2

Part e)

t = 9.14 s

Explanation:

Part a)

Angular speed is given as

\omega = 2\pi f

\omega = 2\pi(\frac{78}{60})

\omega = 8.17 rad/s

Part b)

Since turn table is accelerating uniformly

so we will have

\theta = \frac{\omega_f + \omega_i}{2} t

\theta = \frac{8.17 + 0}{2}(11.9)

2N\pi = 48.6

N = 7.74 rev

Part c)

angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{t}

\alpha = \frac{8.17 - 0}{11.9}

\alpha = 0.69 rad/s^2

Part d)

When its angular speed changes to 120 rpm

then we will have

\omega_2 = 2\pi (\frac{120}{60})

\omega_2 = 12.56 rad/s

number of turns revolved is 15 times

so we have

\omega_f^2 - \omega_i^2 = 2 \alpha \theta

12.56^2 - 8.17^2 = 2\alpha (2\pi\times 15)

\alpha = 0.48 rad/s^2

Part e)

now for uniform acceleration we have

\omega_f - \omega_i = \alpha t

12.56 - 8.17 = 0.48 t

t = 9.14 s

7 0
3 years ago
During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initi
mina [271]

Answer: 0.00000938422m^3

Explanation:

dV=Vø*β*(t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C

β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1= 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 *10^-3 *0.0002*(93.5-16.2)

dV= 0.00000938422m^3

This is the volume of coffee that will spill over the container

4 0
3 years ago
An object has one force acting on it. it is a 33-newton force pointing downward. to create a net force of zero on the object, wh
Alex_Xolod [135]

For this case, the first thing we are going to do is define a reference system.

We define the vertical axis of the reference system, pointing upwards.

Therefore, doing summation of forces in vertical direction we have:

Fy = F - 33

Then, since we want the net force to be equal to zero, then:

F - 33 = 0

From here, we clear the force that we must apply on the object:

F = 33

The positive sign means that the force points upwards.

Answer:

to create a net force of zero on the object you must apply:

33 Newton upwards.

4 0
3 years ago
Read 2 more answers
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