The phenomenon that is occurring is depicted in fig. Induction can be used to provide an explanation for this. As seen in Fig., when a negatively charged plastic rod is pushed close to a metal rod that is initially unaltered, the metal rod's left end picks up positive charges while the right end will pick up negative charges as a result of induction. when the empty metal ball is brought close to the metal rod's right end. The ball's near face subsequently develops a positive charge as a result of induction, and this positive charge attracts the rod since opposite charges are attracted to one another.
<h3>
Define Induction?</h3>
Electromagnetic induction, often known as induction, is the technique of creating electrical current in a conductor by exposing the conductor to a fluctuating magnetic field. Because the magnetic field is thought to have induced the current in the conductor, it is known as induction.
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Answer:
(a) 98 N
(b) 158 N
(c) 38 N
Explanation:
<h2>
Part (a)</h2>
When the acceleration is 0 m/s², the net force on the mass is 0 N. Therefore, the tension force is equal to the weight force due to Newton's Second Law:
- ∑F_y = T - w = ma_y
- ∑F_y = T - w = m(0 m/s²)
- ∑F_y = T - w = 0
- ∑F_y = T = w
Since the tension in the cable and the weight of the mass are equal to each other, we can solve for the weight force of the mass by using:
- w = mg
- w = (10 kg)(9.8 m/s²)
- w = 98 N
Since T = w, we can say that T = 98 N.
<h2>Part (b)</h2>
Let's set the upwards direction to be positive and the downwards direction to be negative. We can use Newton's Second Law to solve for the tension in the cable if the acceleration is 6 m/s² upward:
- ∑F_y = T - w = ma_y
- ∑F_y = T - mg = m(6 m/s²)
- ∑F_y = T - mg = 6m
Plug the known values into the equation and solve for T.
- T - mg = 6m
- T - (10 kg)(9.8 m/s²) = 6(10 kg)
- T - 98 = 60
- T = 158 N
The tension in the cable if the acceleration is +6 m/s² is 158 N.
<h2>
Part (c)</h2>
The process is the same, but this time acceleration is -6 m/s².
- ∑F_y = T - w = ma_y
- ∑F_y = T - mg = m(-6 m/s²)
- ∑F_y = T - mg = -6m
Plug known values into the equation and solve for T.
- T - mg = -6m
- T - (10 kg)(9.8 m/s²) = -6(10 kg)
- T - 98 = -60
- T = 38 N
The tension in the cable if the acceleration is -6 m/s² is 38 N.
i just took the test on edg enuity it was B.The mass of the rocket decreases as fuel is burned, so the acceleration increases.
Answer:
1 Proton, 1 Electron, No Neutrons
Group 1, Period 1
Gases