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Ugo [173]
3 years ago
8

What will be the pressure exerted by the object if 5000N of the force is acting on an area of 200 cm square

Physics
2 answers:
Zepler [3.9K]3 years ago
4 0
It would be 26 hope this helps.
stich3 [128]3 years ago
3 0

Answer:

Answer:25 pascal

Explanation:

Pressure=force÷area

Pressure=5000N÷200cm^2

=25

N/cm^2

=25pascal

Explanation:

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As temperature increases what energy decreases
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Okay, so what temperature does is increase the speed of particles (their kinetic energy). This means that a higher percentage of particles are going to have the required energy (activation energy) to cause a reaction. This however does not actually change the activation energy; all it does is change the amount of particles that HAVE the activation energy. hope that helped
4 0
3 years ago
A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from i
murzikaleks [220]

Answer:

f" = 40779.61 Hz

Explanation:

From the question, we see that the bat is the source of the sound wave and is initially at rest and the object is in motion as the observer, thus;

from the Doppler effect equation, we can calculate the initial observed frequency as:

f' = f(1 - (v_o/v))

We are given;

f = 46.2 kHz = 46200 Hz

v_o = 21.8 m/s

v is speed of sound = 343 m/s

Thus;

f' = 46200(1 - (21/343))

f' = 43371.4285 Hz

In the second stage, we see that the bat is now a stationary observer while the object is now the moving source;

Thus, from doppler effect again but this time with the source going away from the obsever, the new observed frequency is;

f" = f'/(1 + (v_o/v))

f" = 43371.4285/(1 + (21.8/343))

f" = 40779.61 Hz

4 0
2 years ago
How are chargeable cells different from ordinary dry cells​
topjm [15]
Ordinary cells can convert chemical energy to electrical energy only, but rechargeable cells can also store electrical energy into chemical energy and vice versa. You will study more about it in your higher classes. secondary cells can be recharged and used again but dry cells cannot be recharged.
6 0
2 years ago
A person wears a hearing aid that uniformly increases the sound level of all audible frequencies of sound by 28.1 dB. The hearin
ladessa [460]

Answer:

 I₂ = 2.13 x 10⁻⁸ W/m²

Explanation:

given,

increase in sound level = 28.1 dB

frequency of the sound = 250 Hz

intensity = 3.3 x 10⁻¹¹ W/m²

Intensity delivered = ?

the difference of intensity level is give as

\beta_2-\beta_1 = 10log(\dfrac{I_2}{I_o}) - 10log(\dfrac{I_1}{I_o})

\beta_2-\beta_1 = 10(log(\dfrac{I_2}{I_o}) -log(\dfrac{I_1}{I_o}))

\beta_2-\beta_1 = 10(log(\dfrac{I_2}{I_1})

28.1= 10(log(\dfrac{I_2}{I_1})

log\dfrac{I_2}{I_1}=2.81

\dfrac{I_2}{I_1}=10^{2.81}

 I₂ = 645.65 I₁

 I₂ = 645.65 x 3.3 x 10⁻¹¹

 I₂ = 2.13 x 10⁻⁸ W/m²

4 0
3 years ago
A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading
zhannawk [14.2K]

Answer:

See the answers below

Explanation:

To solve this problem we must use the definition of power and work in physics.

a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

P=W/t

where:

P = power = 3.8 [kW] = 3800 [W]

W = work [J]

t = time = 14 [s]

W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

W =F*d

So, the force is equal to:

F=W/d\\F=53200/5.3\\F=10037.73[N]

Now we know that force is defined as the product of mass by gravitation acceleration.

F =m*g

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} }   \\v = 9.6 [m/s]

7 0
3 years ago
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