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3 years ago

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A 0.140-kg baseball traveling 34.0 m/s strikes the catcher's mitt, which, in bringing the ball to rest, recoils backward 19.0 cm

1 answer:

Eva8 [605]3 years ago

4 0

Add then subtract then u will get ur answer

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A ski lift carries people along a 220-meter cable up the side of a mountain. Riders are lifted a total of 110 meters in elevatio

jeka94

The ideal mechanical advantage (IMA) can be determined by the following equation:

IMA= Input distance/Output distance

The Input distance and Output distance are:

Input distance=220 meters

Output distance=110 meters

When you substitute in the equation of the ideal mechanical advantage (IMA), you obtain:

IMA= Input distance/Output distance

IMA= 220 meters/110 meters

IMA=2

3 0

3 years ago

Warsaw, Poland, Olivia Oliver of Nova Scotia broke the world record for being the fastest spinner on ice skates. She achieved a

Mekhanik [1.2K]

Answer:

155.5 rev/min

Explanation:

First, we will calculate the initial moment of inertia I_o. We will consider the ice skater as a rod rotating around its axis. Then, we calculate the final moment of inertia I_f. In this occasion we consider the arms as a rod of length L that is horizontally positioned, L so that the length of an arm is L/2. We will call M_1 the mass that remains close to the rotation axis (90 percent) and M_2 the mass located at the arms (10 percent). Finally, we write the equation for the conservation of angular momentum and we solve for ω_f.

I_o=MR^2/2

=(45)(0.15)^2/2

=0.5 kgm^2

M_1=(0.9)(45)

=40.5 kg

M_2=(0.1)(45)

=4.5 kg

I_f=M_1*R^2/2+M_2*L^2/12

=1.1 kg m^2

I_f*ω_f=I_o*ω_o

ω_f = I_o*ω_o/ I_f

=155.5 rev/min

4 0

3 years ago

An applied force of 20 N is used to accelerate an object to the right across a

vichka [17]

Answer:

$F_{norm} = 100 N$

$F_{net}=10 N$

$\mu = 0.10$

$m = 10 kg$

$a=1.0 m/s^2$

Explanation:

To determine the normal force, we just need to analyze the situation along the vertical direction.

The box along the vertical direction is in equilibrium, so the equation of the forces is

$F_{norm} - F_{grav} = 0$

which means that

$F_{norm} = F_{grav} = 100 N$

The net force can be determined by looking at the situation along the horizontal direction (since the net force in the vertical direction) is zero. Here we have:

- An applied force of 20 N forward, $F_{app} = 20 N$

- A frictional force of 10 N backward, $F_{frict} = 10 N$

So, the net force is

$F_{net}=F_{app}-F_{frict}=20-10 = +10 N$ in the forward direction

The expression for the frictional force is

$F_{frict} = \mu F_{norm}$

where $\mu$ is the coefficient of friction. Solving for $\mu$ ,

$\mu = \frac{F_{frict}}{F_{norm}}=\frac{10}{100}=0.10$

The force of gravity is given by

$F_{grav}=mg$

where m is the mass of the object and $g=10 m/s^2$ . Solving for m, we find the mass of the object:

$m=\frac{F_{grav}}{g}=\frac{100}{10}=10 kg$

Finally, the acceleration can be found by using Newton's second law

$F_{net} = ma$

where a is the acceleration. Solving for a,

$a=\frac{F_{net}}{m}=\frac{10}{10}=1.0 m/s^2$

4 0

3 years ago

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT include

Sphinxa [80]

Answer:

1753246.75325 V/m

Explanation:

d = Distance of separation = 1.54 cm

V = Potential difference = 27 kV

When the voltage is divided by the distance between the plates we get the electric field.

Electric field is given by

$E=\dfrac{V}{d}\\\Rightarrow E=\dfrac{27\times 10^3}{1.54\times 10^{-2}}\\\Rightarrow E=1753246.75325\ V/m$

The magnitude of the electric field in the region between the plates is 1753246.75325 V/m

5 0

3 years ago

PLEASE HURRY I'M BEING TIMED

DIA [1.3K]

Top of first hill:
high PE
low KE

bottom first hill:
low PE
high KE

Friction slows the speed of the roller coaster

7 0

3 years ago