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3 years ago

True or false Volleyball

Physics

1 answer:

emmainna [20.7K]3 years ago

4 0

True statement:

THE SAME PERSON IS NOT ALLOWED TO HIT THE BALL TWO TIMES IN A ROW.

False statements:

IN VOLLEYBALL, TEAMS MUST WIN BY TWO.

EACH TEAM MAY HIT THE BALL UP TO THREE TIMES.

Explanation:

There is no any rule in volleyball that states that a team is only allowed to hit the ball trice. A team can hit as much as they can but not by a single player.
The same player can hit the ball only once. After one hit, the striking player must be changed with in the team.
A team can win with any score, it doesn't need to be only two points.

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Andrews [41]

Answer:

t = 5.4 s

Explanation:

from the question we are given :

height (s) = 20 m

mass of paint (Mp) = 4 kg

mass of nails (Mn) = 3 kg

acceleration due to gravity (g) = 9.8 m/s^{2}

The net force accelerating the can of paint should be equal to the difference in weight of the can of paint and the can of nails.

weight of nails = mass of nails x g = 3 x 9.8 = 29.4 N

weight of paint = mass nails x g = 4 x 9.8 = 39.2 N

net force = 39.2 - 29.4 = 9.8 N

net force = total mass x acceleration

9.8 = (3 +4) x a

a = 1.4 m/s^{2}

from S = Ut + 0.5at^{2} we can get the time the carpenter has to catch the nails

where U is the initial velocity and is 0 since the can was initially at

rest

20 = (0 x t) + (0.5 x 1.4 x t^{2})

20 = 0.7 x t^{2}

t^{2} = 28.6

t = 5.4 s

8 0

3 years ago

The ball is displaced to the left and then oscillates backwards and forwards between the two plates. The ball touches a plate on

ELEN [110]

Answer:

Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere

Explanation:

The formula to be used here is

Q = It

where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C

I is current and it is measured in ampere (amps or A); unknown

t is time and it is measured in seconds (s); 0.05 s

Since, average current is what is unknown

I =Q/t

I = 0.000000028/0.05

I = 5.6 × 10⁻⁷ A

Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere

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3 years ago

A force of 50 N stretches a string by 4 cm,calculate the elastic constant.

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Answer:

50/0.04= answer

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3 years ago

A spinning disk is rotating at a rate of 5 rad/s in the positive counterclock-wise direction. If the disk is subjected to an ang

Anit [1.1K]

Answer:

ωf = 13 rad/s

Explanation:

The angular acceleration, by definition, is just the rate of change of the angular velocity with respect to time, as follows:
α = Δω/Δt = (ωf-ω₀) / (tfi-t₀)
Choosing t₀ = 0, and rearranging terms, we have

$\omega_{f} = \omega_{o} + \alpha *t (1)$

where ω₀ = 5 rad/s, t = 4 s, α = 2 rad/s2

Replacing these values in (1) and solving for ωf, we get:

$\omega_{f} = 5 rad/s + (2 rad/s2*4 s) = 13 rad/s (2)$

The wheel's angular velocity after 4s is 13 rad/s.

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3 years ago

A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t

Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

$h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m$

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height is given by;

v = u - gt

u = gt

$t = \frac{u}{g}$

Time of flight, T = 2t

$T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s$

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0

3 years ago