Let u = initial vertical velocity.
Assume that
g = 9.81 m/s²,
Wind resistance is ignored.
When t = 0.220 s, the height is h = 0.537 m. Therefore
0.537 m = (u m/s)*(0.220 s) - (1/2)*(9.81 m/s²)*(0.220 s)²
0.537 = 0.22u - 0.2372
u = 3.519 m/s
The upward velocity after 0.220 s is
v = 3.519 - 9.81*0.22 = 1.363 m/s
At maximum height, the upward velocity is zero. The maximum height, H, is given by
(3.519 m/s)² - 2*(9.81 m/s²)*(H m) = 0
12.3834 - 19.6H = 0
H = 0.632 m
It goes higher by 0.632 - 0.537 = 0.095 m
Answers:
(a) The initial speed is 3.519 m/s.
(b) The speed at 0.537 m height is 1.363 m/s.
(c) It goes higher by 0.095 m.
Answer:
27 . 10^-7 or 27/1000
Explanation:
We use the Coulomb Law
k = Coloumb Constant
q1 and q2 are the charges
d is the distance between the spheres
Answer:
<h2>0.5 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
From the question we have
We have the final answer as
<h3>0.5 m/s²</h3>
Hope this helps you
Wavelength times frequency = speed of light
7.5E14 x wavelength = 300,000 m/s
Wavelength in meters = 300,000 divided by 7.5E14
3 as a single number is considered a sf
