Answer:
34.75m
Explanation:
Parameters given:
Net force, F = 320N
Work done by net force, W = 4700 N
Angle, θ = 65º
Work done at an angle is given as:
W = F * d * cosθ
Where d = distance travelled
θ is the angle between the force and the direction of motion.
Therefore,
4700 = 320 * d * cos65
=> d = 4700/(320 * cos65)
d = 34.75 m
I hope I can help! :)
A concave mirror is when the object is anywhere from infinity to focus the image so form will be real and inverted.
And when the object is between pole and focus of concave mirror then image so formed will be virtual and erect and the size of image is greater than size of object.
So, the answer would be "where light rays disperse."
Have a great day/evening/night! :)
Let me know if you have any additional questions!
-Kappifilms
Answer:
C. Technician B
Explanation:
Excessive Galvanic activity:
To check for excessive galvanic activity, voltmeter is used to check the coolant. If the voltmeter is giving a reading greater than 0.5 V, there is excessive galvanic activity. Excessive galvanic activity is solved by flushing the coolant fluid from engine and refiling it.
Electrolysis problem:
When the system is not properly ground, the cooling system accepts stray current and the coolant becomes an electrolyte which might eat up the radiator. To test for excessive electrolysis, start the engine and turn on all electrical accessories, if the reading is more than 0.5 V, there is electrolysis problem. Ground wires and connections should be checked at this point to stop stray current.
In our case, the first reading is 0.2 V(engine turned off) which is normal and there is no excessive galvanic activity. This means that Technician A is not correct. The second reading is 0.8 V when the engine and all electrical accessories are turned on. This reading is greater than 0.5 V which means there is an electrolysis problem. This means that Technician B is correct and ground wires and connections should be inspected and repaired.
Gamma rays are mostly absorbed. So its probably
Gamma Rays
Answer:
Explanation:
Initial kinetic energy of particle
= 1/2 m V²
= .5 x .208 x 1.26²
= .165 J
Work done by force = force x displacement
= .766 x .195
= .149 J
This energy will be added up .
Total final kinetic energy
= initial kinetic energy + work done on the particle
= .165 + .149 J
= .314 J .
