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spayn [35]
3 years ago
11

Must be put in groups of 14 square units or 16 square units triangle EFG

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

Area 14 = PQRS + UVW; Area 16 = ABCD + EFG

Step-by-step explanation:

PQRS:  A = lw     = 7 × 2        = 14

ABCD: A = lw     = 4 × 4        = 16

UVW:  A  = ½bh = ½ × 7 × 4 = 14

EFG:    A = ½bh = ½ × 8 × 4 = 16

Area 14 = PQRS + UVW

Area 16 = ABCD + EFG

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3 years ago
Y is such that 4y _ 7<= 3y and 3y <= 5y +8. What range of values of y satisfies both inequalities
fgiga [73]

Answer:

<h3>-4≤y≤7</h3>

Step-by-step explanation:

Given the inequality expressions

4y - 7 ≤ 3y and 3y≤5y+8

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Collect like terms

4y - 3y ≤ 7

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For  3y≤5y+8

Collect like terms

3y - 5y ≤ 8

-2y ≤ 8

y ≥ 8/-2

y ≥ -4

Combining both solutions

-4≤y≤7

<em>Hence the range of values of y that satisfies both inequalities is -4≤y≤7</em>

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dolphi86 [110]

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3 0
3 years ago
What is the radius of a cylinder if the volume is 192 pi and has a height of 12cm
kkurt [141]
Volume =πr²h

192π = πr²(12)        // Plug the value of the volume and the height in

r² = 192π ÷ 12π       // divide by 12π on both sides

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r = √16                    // square root both sides

r = 4        

------------------------------------------------------------
Answer: The radius is 4 cm.
------------------------------------------------------------
5 0
4 years ago
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