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spayn [35]
3 years ago
11

Must be put in groups of 14 square units or 16 square units triangle EFG

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

Area 14 = PQRS + UVW; Area 16 = ABCD + EFG

Step-by-step explanation:

PQRS:  A = lw     = 7 × 2        = 14

ABCD: A = lw     = 4 × 4        = 16

UVW:  A  = ½bh = ½ × 7 × 4 = 14

EFG:    A = ½bh = ½ × 8 × 4 = 16

Area 14 = PQRS + UVW

Area 16 = ABCD + EFG

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A store is having a sale on trail mix and jelly beans. For 5 pounds of trail mix and 6 pounds of jelly beans the total cost is $
inna [77]

The cost for each pound of trail mix and each pound of jelly is given below.

Step-by-step explanation:

Let t = cost/pound of trail mix

Let j = cost/pound of jelly beans

5t + 6j = 35

3t + 2j = 15  =  > 2j = 15 - 3t

5t + 3(15 - 3t) = 35

5t + 45 - 9t = 35

- 4t + 45 = 35

- 4t  =  - 10

4t = 10

t = 2.5

3(2.5) + 2j = 15

7.5 + 2j = 15

2j = 7.5

j = 3.75

7 0
3 years ago
WHY IS THIS GETTING DELETED?? I NEED HELP
aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

\dfrac{(5\times5)^k}{5^{-8}} = 5^3

or

\dfrac{5\times 5^k}{5^{-8}} = 5^3

If the first one is what you intended, then

\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3

and it follows that

2<em>k</em> + 8 = 3   ==>   2<em>k</em> = -5   ==>   <em>k</em> = -5/2

If you meant the second one, then

\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3

which would give

<em>k</em> + 9 = 3   ==>   <em>k</em> = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0
3 years ago
Expand and simplify: (x-5)(x+5)
stealth61 [152]
X^2-5x+5x-25 (multiply (x-5) with (x+5))
X^2-25 ( -5x+5x =0)





5 0
3 years ago
Read 2 more answers
The solution of the equation 2d - 6 = 5 is _____.
xeze [42]

Answer: d = 11/2 or 5 1/2

Step-by-step explanation:

2d - 6 = 5

    + 6  + 6

2d = 11

/2     /2

d = 11/2 or 5 1/2

7 0
3 years ago
Read 2 more answers
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
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