Answer:
120,000 J
Explanation:
The work done by a force applied parallel to an object is given by:
where
F is the magnitude of the force applied
d is the displacement of the object
In this problem:
F = 8000 N is the force exerted by the elevator to lift the passenger
d = 15 m is the displacement of the elevator
Therefore, the work done in this situation is
So, the work done is 120,000 J.
Edges of tectonic plates where the shock waves resonate through the ground with larger amplitudes
To answer this question, two equations are needed.
F = m * a (force = mass * accelaration)
Vf =Vi + (a * t) (final velocity = initial velocity + (accelaration * time)
Knowing that the force is 100 N and the mass is 50 kg we can use the first equation to solve for the acceleration which would be 2 m/s^2.
Plugging in all we know to the second equation we get:
150 m/s = 100 m/s + (2 m/s^2 * t)
This gives us t = 25 seconds