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Archy [21]
3 years ago
10

Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented

parallel to the plane of the slits. The slits are illuminated by a monochromatic and coherent light source with a wavelength of ? = 648 nm. A wave from each slit propagates to the screen. The interference pattern shows a peak at the center of the screen (m=0) and then alternating minima and maxima.
At what angle from the beam axis will the first (m=1) maximum appear? (You can safely use the small angle approximation.)
Physics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

\theta = 0.195^0

Explanation:

wavelength \lambda  = 648 nm \   = 648*10^{-9}m

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})

\theta = 0.195^0

The first maximum will appear at an angle \theta = 0.195^0 from the beam axis

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In order for a chemical equation to be balanced, the condition which must be met is that the number of atoms in the reactants equals the number of atoms in the products.

This ultimately implies that, the mass and charge of the chemical equation are both balanced properly.

In Chemistry, all chemical equation must follow or be in accordance with the Law of Conservation of Mass, which states that mass can neither be created nor destroyed by either a physical transformation or a chemical reaction but transformed from one form to another in an isolated (closed) system.

One of the step used for balancing chemical equations is to count the atoms in each substance in the reactants and products.

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For the reactant side:

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Detailed explanation and calculation is shown in the image below

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