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Archy [21]
3 years ago
10

Two slits separated by a distance of d = 0.190 mm are located at a distance of D = 1.91 m from a screen. The screen is oriented

parallel to the plane of the slits. The slits are illuminated by a monochromatic and coherent light source with a wavelength of ? = 648 nm. A wave from each slit propagates to the screen. The interference pattern shows a peak at the center of the screen (m=0) and then alternating minima and maxima.
At what angle from the beam axis will the first (m=1) maximum appear? (You can safely use the small angle approximation.)
Physics
1 answer:
Svetlanka [38]3 years ago
3 0

Answer:

\theta = 0.195^0

Explanation:

wavelength \lambda  = 648 nm \   = 648*10^{-9}m

d = 0.190 mm = 0.190 × 10⁻³ m

D = 1.91 m

By using the formula:

dsin \theta = n \lambda\\\\\theta = sin^{(-1)}(\frac{n \lambda}{d})\\\\\\\theta = sin^{(-1)}(\frac{1*648*10^{-9}}{0.190*10^{-3}})

\theta = 0.195^0

The first maximum will appear at an angle \theta = 0.195^0 from the beam axis

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