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stellarik [79]
3 years ago
6

Andy has set a goal to be able to run 65 laps on the PACER by the end of the school year. This is an example of a ____.

Physics
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

The answer is long- term goal

Explanation:

You might be interested in
1. Suppose you know that the net force on an object is zero. What can you say about
Kryger [21]

If the net force on an object is zero, then ...

a). The object's acceleration is zero.

b). The object's velocity is a constant speed in a straight line.

Note: (a) and (b) both say the same thing.

3 0
3 years ago
A 1 cm2 silicon solar cell has a saturation current of 10A and is illuminated with sunlight yielding a short-circuit photocurren
Yuki888 [10]

Answer:

The answer is "13% and 83%"

Explanation:

The highest power is generated for:

\to \frac{dP}{dV_a}=0= I_s(e^{\frac{V_m}{V_t}} -1)-I_{Ph} +\frac{V_m}{V_t} I_s e^{\frac{V_m}{V_t}}

 Where voltage, V_m, was its calculated maximum power wattage.  This same following transcend national stable coins the power output:

\to V_m=V_t \ In \frac{1+\frac{I_{ph}}{I_s}}{1+\frac{V_{m}}{V_t}}

The accompanying consecutive values of V_m are done utilizing iteration and an initial value of 0.5 V:

\to V_m = 0.5,\  0.542,\  0.540 \ V

Efficacy is equivalent to:

\eta = |\frac{V_{m} I_{m}}{p_{in}}| =\frac{0.54 \times 0.024}{0.1}=1.3\%

Currently, I_m was calculated with the formula of voltage V_m (4.6.1) as well as the sun is presumed to produce  100 \frac{mW}{cm^2} of power.

The fulfillment factor is equal to:

fill factor= \frac{V_{m} I_{m}}{V_{oc}I_{sc}}= \frac{0.54 \times 0.024}{0.62 \times 0.025}=83\%

where open circuit tension of equations (4.6.1) and I = 0. is calculated. The current is equal to the total current of the photo.

5 0
3 years ago
If you can answer both, please do. But if you can't, just answer one.
Setler [38]

Answer:

1.The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

                                      p = m(u - v)

                                         = 7 (3.5 - 0)

                                         = 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

                                           F = p / t

                                               = 24.5 / 2

                                               = 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

2.

We have: F = m × v/t

Here, m = 8500 Kg

v = 20 m/s

t = 10 s

Substitute their values into the expression,  

F = 8500 × 20/10

F = 8500 × 2

F = 17000 N

In short, final answer would be 17000 N

Hope this helps!!

7 0
3 years ago
A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10
IRINA_888 [86]

Complete Question:

A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rads/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to

Answer:

t= 16.7 sec.

Explanation:

As we are told that the wheel is accelerating uniformly, we can apply the definition of angular acceleration to its value:

γ = (ωf -ω₀) / t

If the wheel was at rest at t-= 0.00 s, the angular acceleration is given by the following equation:

γ = ωf / t = 25 rad/sec / 10 sec = 2.5 rad/sec².

When the power is shut off, as the deceleration is uniform, we can apply the same equation as above, with ωf = 0, and ω₀ = 25 rad/sec, and γ = -1.5 rad/sec, as follows:

γ= (ωf-ω₀) /Δt⇒Δt = (0-25 rad/sec) / (-1.5 rad/sec²) = 16.7 sec

8 0
3 years ago
Samantha's teacher asks her to describe motion in one dimension. This type of motion is always
Whitepunk [10]

A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.

Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.

In Science, the motion of an object or physical body is described in terms of the following parameters:

  • Speed
  • Force
  • Acceleration
  • Distance
  • Time

Furthermore, there are three (3) forms of motion based on dimension and these include:

1. Motion in one dimension

2. Motion in two dimension

3. Motion in three dimension

A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.

Read more on motion here: brainly.com/question/17675825

6 0
3 years ago
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