Answer:
The answer to your question is 203.8 g
Explanation:
Data
Average atomic mass = ?
Centium-200
Centium-203
Centium-209
Equal amounts
Process
1.- Determine the abundance of each isotope.
If they are in equal amounts in nature, just divide 100 by 3
100/3 = 33.33 % or 0.333
2.- Determine the Average atomic mass
Average atomic mass = Atomic mass 1 x abundance + Atomic mass 2 x
abundance + Atomic mass 3 x abundance
- Substitution
Average atomic mass = 200 x 0.333 + 203 x 0.333 + 209 x 0.333
- Simplification
Average atomic mass = 66.6 + 67.6 + 69.6
Result
Average atomic mass = 203.8 g
The only answer that makes sense is A.
Warm wet forests is a rainforest, arctic foxes are biotic, not abiotic, and little rainfall extreme temperatures is a desert.
From a stock solution of 3.00 m nitric acid, 9.391 ml of stock solution is needed to create a 0.161 m nitric acid solution, which has a total volume of 175 ml of the diluted solution.
A chemical reagent is present in vast quantities as a stock solution. It has a uniform concentration. Examples of typical stock solutions in laboratories are nitric acid and hydrochloric acid. These play a critical role in creating the titration-related solution preparations.
We know the formula for dilution type problems
M1 VI = M2 V 2
Where,
M, = initial molarity
V , = initial Volume
M2 = final molarity
V 2 = final Volume
Hene given -
M, = 3.00 M
VI = ?
M2 = 0.161M
V 2 = 175 ml
Accordingly ' MI V1 = M2 V 2
V1 =
V1= (0.161M*175ml)/ 3.00M
v1 = 9.391
The required volume of Stock solution is 9.391ml.
Learn more about Stock solution here
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Answer:
I don't know the answer of this question but thanks for the points.