Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation.
To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign.
Pb(s) --> Pb2+ +2e- E0 = +0.13 V
Ag+ + e- ---> Ag E0 = +0.80 V
Adding up the E0's would yield an overall electric cell potential of +0.93 V.
Answer:
1.25 M
Explanation:
Step 1: Given data
Mass of KI (solute): 20.68 g
Volume of the solution: 100 mL (0.100 L)
Step 2: Calculate the moles of solute
The molar mass of KI is 166.00 g/mol.
20.68 g × 1 mol/166.00 g = 0.1246 mol
Step 3: Calculate the molar concentration of KI
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.1246 mol/0.100 L= 1.25 M
Maturation replaces breath under this states of stress where the o2 allow by muscle cells is more prominent than oxygen is accessible.
The answer is true, this is how dams work as the water goes through ot it pushed the turbines inside to generate electricity.
I hope this helps.
Answer:
1. The physical states of the reactants and products.
2. The concentration of the reactants and products.
3. The conditions such as temperature, pressure or catalyst etc which affect the reaction.
4. The heat changes accompanying the reaction i.e. whether heat is evolved or absorbed during the reaction.
Explanation:
Hope it helps! ^w^
