In order to become a scientific theory the three
categories that it must pass are the following:
1) Can the phenomena be recreated in a laboratory setting?
2) Can variables be changed, yet still result in like observations?
3) Is the phenomena truly natural or was it the result of a man-made force
enacting upon it?
Answer:
74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.
Explanation:
The balanced reaction is:
Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- Ca(NO₃)₂: 1 mole
- CaCO₃: 1 mole
- NaNO₃: 2 mole
Being the molar mass of the compounds:
- Na₂CO₃: 106 g/mole
- Ca(NO₃)₂: 164 g/mole
- CaCO₃: 100 g/mole
- NaNO₃: 85 g/mole
then by stoichiometry the following quantities of mass participate in the reaction:
- Na₂CO₃: 1 mole* 106 g/mole= 106 g
- Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
- CaCO₃: 1 mole* 100 g/mole= 100 g
- NaNO₃: 2 mole* 85 g/mole= 170 g
You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of CaCO₃?
mass of CaCO₃= 74.81 grams
<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>
Answer:
128g
Explanation:
Given parameters:
Mass of carbon = 48g
Mass of carbon dioxide = 176g
Unknown:
Mass of oxygen that reacted = ?
Solution:
Every chemical reaction must obey the law of conservation of mass. It states that "in a chemical reaction, matter is neither created nor destroyed" .
So;
Mass of carbon + Mass of oxygen = Mass of carbon dioxide
Mass of oxygen = Mass of carbon dioxide - Mass of carbon
Mass of oxygen = 176 - 48 = 128g
Answer:
length of wire = 38.82 m
Explanation:
∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm
∴ m spool = 1 Lb = 453.592 g
∴ ρ = 8.92 g/cm³
cross section area:
⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²
⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )
⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m
<span>The solution to the problem is as follows:
125/58.69 = 2.12 mol
</span>
Therefore, there are 2.12 moles of <span>nickel (Ni) atoms are in 125 g Ni.
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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