In 250 mL of volumetric flask add 0.975875 grams of
and dissolve it in the 250 mL of water.
Given:
The solid of calcium fluoride.
To prepare:
The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.
Method:
Molarity of the fluoride ion solution needed = M = 0.100 M
The volume of the fluoride ion solution needed = V = 250 mL

The moles of fluoride ion needed = n
According to the definition of molarity:

Moles of fluoride ion = 0.025 mol
We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.

According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:

Moles of calcium fluoride = 0.0125 mol
Mass of calcium fluoride needed to prepare the solution :

Preparation:
- Weight 0.975875 grams of calcium fluoride
- Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
- Now add a small amount of water to dissolve the calcium fluoride completely.
- After this add more water up to the mark of the volumetric flask of volume 250 mL.
Learn more about molarity of solution ere:
brainly.com/question/10053901?referrer=searchResults
brainly.com/question/10270173?referrer=searchResults
Answer: The rate of the forward reaction increases.+The concentration of
products increases. /The rate of the reverse reaction increases.+The concentration of products decreases.
Explanation: I got this right on Edmentum.
B because it shows the COOCH
Answer:
francium, caesium, helium
Answer:
(1) the surface area of the solute,
(2) the temperature of the solvent,
(3) the amount of agitation that occurs when the solute and the solvent are mixed.
Explanation: