Answer:
a producer and consumer relationship how several food chains and related.
I'm not sure if this is what you're looking for, but I suppose you would have to have the solute and the solution to balance the reaction.
Answer:
5
Explanation:
Count the digits after the first non zero number, any number after that (even zero) counts.
Hope that helped!!! k
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
Question:
The options are;
a. 10. mL of 1 M HCl(aq) at 10.oC
b. 10. mL of 1 M HCl(aq) at 25oC
c. 10. mL of 3 M HCl(aq) at 10.oC
d. 10. mL of 3 M HCl(aq) at 25oC
Answer:
The correct option is;
d. 10 mL of 3 M HCl(aq) at 25 °C
Explanation:
Factors that influence the rate of the reaction include;
Concentration and
Temperature
Concentration
An increase in concentration leads to a increased number of interaction among the the reacting components of HCl and iron filings such that the number of effective interaction or the rate of the reaction increases, therefore, a 10 mL 3 M HCl will react faster than a 10 mL of 1 M HCl.
Temperature
When the temperature of the reacting HCl is increased, the energy within the reacting system increases leading to an increase in the number of high energy collisions which results in an increased reaction rate, therefore, HCl at 25 °C will react faster than HCl at 10 °C.
Hence the correct option is 10 mL of 3 M HCl(aq) at 25 °C.
