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olchik [2.2K]
4 years ago
10

Which of the following compounds will not possess dipole dipole interactions between its molecules?A. HBr.B. CO2.C. PH.D. NO.E.

SCl.
Chemistry
1 answer:
Black_prince [1.1K]4 years ago
6 0

Answer:

B. CO2

Explanation:

Because its a neutral compound hence lacks any form of dipole dipole interaction

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Kipish [7]
4.1 billion years ago
6 0
3 years ago
A hypothetical AX type of ceramic material is known to have a density of 3.55 g/cm3 and a unit cell of cubic symmetry with a cel
postnew [5]

Explanation:

For AX type ceramic material, the number of formula per unit cells is as follows.

         \rho = \frac{n'(A_{c} + A_{A})}{V_{C}N_{A}}

or,     n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}

where,   n' = no. of formula units per cell

           A_{c} = molecular weight of cation = 90.5 g/mol

           A_{a} = molecular weight of anion = 37.3 g/mol

          V_{c} = volume of cubic cell = 3.55 g/cm^{3}

           a = edge length of unit cell = 3.9 \times 10^{-8} cm

        N_{A} = Avogadro's number = 6.023 \times 10^{23}

          \rho = density = 3.55 g/cm^{3}

Now, putting the given values into the above formula as follows.

           n' = \frac{\rho a^{3}N_{A}}{(A_{c} + A_{A})}

                      = \frac{3.55 g/cm^{3} \times (3.9 \times 10^{-8})^{3} \times 6.023 \times 10^{23}}{(90.5 + 37.3)}

                     = 0.9

                    = 1 (approx)

Therefore, we can conclude that out of the given options crystal structure of cesium chloride is possible for this material.

3 0
3 years ago
Increasing the temperature of a particular liquid from 298 K to 318 K causes its vapor pressure to double. What is the enthalpy
Delvig [45]

Answer:

27.3 kJ/mol

Explanation:

Step 1: Given data

  • Temperature 1 (T₁): 298 K
  • Vapor pressure 1 (P₁): P₁
  • Temperature 2 (T₂): 318 K
  • Vapor pressure 2 (P₂): 2 P₁

Step 2: Calculate the enthalpy of vaporization of this liquid

We will use the Clausius–Clapeyron equation.

ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)

ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)

ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol

5 0
3 years ago
Which of the four hypothetical substances you investigated would be most harmful to living organisms
Hoochie [10]
I believe the most harmful substance would be element C, this is because element C has a very long half life therefore it has a very slow rate of a decay. Half life of a substance it the time taken for substance to decay to half its original mass or amount.
5 0
3 years ago
Which liquid substance would evaporate most quickly in the open air at 20°C? Explain our answer
kati45 [8]

Answer:

mp -5; bp 30

Explanation:

That will be a liquid at room temperature, and it will evaporate quite quickly. Room temperature is generally considered 20 degrees Celsius. Choice B melts from a solid to a liquid at -5 degrees, so it's a liquid at room temperature as long as the boiling point is higher than 20 degrees.

3 0
3 years ago
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