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olchik [2.2K]
3 years ago
10

Which of the following compounds will not possess dipole dipole interactions between its molecules?A. HBr.B. CO2.C. PH.D. NO.E.

SCl.
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

B. CO2

Explanation:

Because its a neutral compound hence lacks any form of dipole dipole interaction

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In order to derive a simplified version of the Nernst equation by assuming standard temperature we can substitute which of the f
Nikitich [7]

Answer:

c. 298 K

Explanation:

Nernst equation is an equation used in electrochemistry that relates the reduction potential of a reaction with the standard potential, temperature and concentrations of the reactants in that are been reducted and oxidized. The formula is:

E = E° - RT / nF ln [Red] / [Ox]

<em>Where R is gas constant (8.314J/molK), T is absolute temperature (In Kelvin), n are moles of electrons and F is faraday constant (K/Volt*mol)</em>

<em />

In electrochemistry, standard temperature is taken as 298K. That means by assuming standard temperature we can substitute T as:

<h3>c. 298 K</h3>
5 0
3 years ago
Accuracy vs. Precision
Oksi-84 [34.3K]

Answer:

Accuracy is the closeness to the specific target and precision is the closeness of the measurements to each other.

3 0
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Rocks are solids composed of one or more minerals true or false
Yuki888 [10]
The answer is true
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8 0
3 years ago
Hurry!!
pishuonlain [190]

Answer:

condensation is the answer

6 0
2 years ago
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Calculate the percent ionization of formic acid (hco2h) in a solution that is 0.311 m in formic acid and 0.189 m in sodium forma
ohaa [14]
<span>Answer: 0.094%


</span><span>Explanation:
</span>
<span></span><span /><span>
1) Equilibrium chemical equation:
</span><span />

<span>Only the ionization of the formic acid is the important part.
</span><span />

<span>HCOOH(aq) ⇄ HCOO⁻(aq) + H⁺(aq).
</span><span />

<span>2) Mass balance:
</span><span />

<span>                   HCOOH(aq)     HCOO⁻(aq)     H⁺(aq).

Start             0.311                 0.189

Reaction       - x                      +x                   +x

Final             0.311 - x          0.189 + x            x


3) Acid constant equation:
</span><span />

<span>Ka = [HCOO-] [N+] / [HCOOH] = (0.189 + x) x / (0.311 -x)
</span><span />

<span>= (0.189 + x )x / (0.311 - x) = 0.000177


4) Solve the equation:


You can solve it exactly (it will lead to a quadratic equation so you can use the quadratiic formula). I suggest to use the fact that x is much much smaller than 0.189 and 0.311.
</span><span />

<span>With that approximation the equation to solve becomes:


</span><span>0.1890x / 0.311 = 0.000177, which leads to:</span>
<span /><span>
x = 0.000177 x 0.311 / 0.189 = 2.91 x 10⁻⁴ M


5) With that number, the percent of ionization (alfa) is:
</span><span />

<span>percent of ionization = (moles ionized / initial moles) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (concentration of ions / initial concentration) x 100 =
</span><span>
</span><span>
</span><span>percent ionization = (0.000291 / 0.311)x 100 = 0.0936% = 0.094%
</span>
<span></span><span />
8 0
3 years ago
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