A Savings Vehicle is an effective way to hold your savings. It could be a savings account. But some requires a high minimum balance such as Certificate of Deposit (CD). It is generally issued by commercial banks. It is a time deposit too and restricts you from withdrawing funds.
Answer:
It prints "goodbye" 8 times.
Explanation:
The loop being described in this scenario would print "goodbye" 8 times. It would not include numbers detailing the range since the loop instructions only state for the system to print("goodbye") and nothing else. Also, it would only print it 8 times because in a range the endpoint is not included, this is mainly because in programming data structures tend to run on 0-based indexing.
Answer:
When a programmer tries to access an item in an array cell whose index is greater than or equal to the array's logical size, this data element or item is garbage. This means that currently, the item is not the part of the program's useful data. Garbage contains objects or data which will not be used by a program running on it. So the value returned could be either of the two:
- Value would be an arbitrary or random number if it is an array of numbers. Arbitrary means that the value is not predefined or specified in advance.
- Value returned would be null if it is an array of objects.
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
They cannot legally check it without a warrant.
Depending on the circumstances of the arrest/check, and the method of seizure of the mobile device, you are subject to a certain set of rights, laws, or protections. First off, know that it is your right to decline the warrantless search of your mobile phone. If you are arrested or taken into police custody, you should verbally state that you do not consent to a search of your devices. A law enforcement agency is only permitted to conduct a warrantless search of your device if a compelling case for an emergency can be made.
If the authorities are using evidence obtained through an unlawful search of your mobile device against you in a criminal proceeding, you can move for that data to be suppressed under the Fourth Amendment right to freedom from incidental seizures.
