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WINSTONCH [101]
3 years ago
8

What is the first step in glycolysis

Physics
1 answer:
mario62 [17]3 years ago
4 0
Hexokinase is the correct answer
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Energy input remains constant and voltage remains the same in a circuit, but current decreases. Which must be happening?
RUDIKE [14]
A) the resistance is increasing

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3 years ago
What is the force needed to give a .25 kg arrow an acceleration of 196m/s2?
Rzqust [24]
<span>49N is the force needed to give a .25 kg arrow an acceleration of 196m/s2. F =ma ⇒ =( 0.25kg)(196m/s2) = 49N if the arrow is shot horizontally where the applied force is entirely in the x-direction.</span>
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3 years ago
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Which of the following processes DOES NOT occur during the convective transfer of heat within a container of air? Group of answe
vovangra [49]

The volume of a warmed part of the air is reduced and its density increases.

Explanation:

In a convective form of heat transfer, the volume of a warmed part of air is not reduced and its density does not increase.

During convection, heat causes the warm part of the air to expand and its volume increases. When volume increases, density is reduced.

  • Convection is a form of heat transfer that involves the actual movement of particles of the medium.
  • It usually occurs in fluids i.e gases and liquids.
  • In convection, the cold part exerts a buoyant force on the warmer air below and causes it to rise.
  • As the warmer part is rising the cooler part replaces it and a convective cell is formed in the process.

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Energy transfer in the sun brainly.com/question/1140127

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7 0
3 years ago
The source of earth's magnetic field is best explained by _____.
WITCHER [35]
<span>The Dynamo Theory

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4 0
3 years ago
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A tissue sample at 275 K is submerged in 2 kg of liquid nitrogen at 70 K for cryopreservation. The final temperature of the nitr
kirill115 [55]

Answer:

The heat capacity of a sample is 37.7 J/K.

Explanation:

Given that,

Submerged temperature of tissue sample = 275 K

Mass of liquid nitrogen= 2 kg

Temperature = 70 K

Final temperature = 75 K

We need to calculate the heat

Using formula of heat

Q=mc(T_{f}-T_{i})

Put the value into the formula

Q=2\times1.039\times10^{3}\times(75-70)

Q=10390\ J

We need to calculate the heat capacity of a sample

Using formula of heat capacity

\Delta S=\dfrac{Q}{T}

Put the value into the formula

\Delta S=\dfrac{10390}{275}

\Delta S=37.7\ J/K

Hence, The heat capacity of a sample is 37.7 J/K.

7 0
3 years ago
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