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Sergeeva-Olga [200]
3 years ago
12

The noble gases are the least ____ of any elements on the periodic table. The___ form acidic compounds with hydrogen. The haloge

ns are the most reactive among all the____ .
Physics
2 answers:
dimaraw [331]3 years ago
8 0

Answer:

1. reactive 2. halogens 3. nonmetals

Explanation:

Taya2010 [7]3 years ago
6 0

Explanation :

Noble gases are the elements of group 18. This series contains helium, neon, radon krypton and radon.

The noble gases are the least reactive of any elements on the periodic table. This is because they have eight valance electrons in its outermost shell.

Non-metals or poly atomic ions forms  acidic compounds with hydrogen. For example : HCl, H_2SO_4 \ and\ H_3PO_4 etc forms acidic compounds with hydrogen.

The halogens are the most reactive among all the elements. This is because halogens suddenly combines with most of the metals. They are never seen uncombined in nature.

For example : Chlorine, fluorine and astatine are some halogens.

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Can someone please help me with this physics question? I'm desperate!
Lelu [443]

Answer:

a) 2·√10 seconds

b) Linda should be approximately 30.6 meters

c) Jenny's speed at the 100-m mark is approximately 6.325 m/s

Explanation:

The speed with which Linda is running = 8.6 m/s

The point Jenny starts = The 80-m mark

The acceleration of Jenny = 1.0 m/s²

a) The time it takes Jenny to run from the 80-m mark to the 100-m mark, <em>t</em>, is given as follows

Δs = u·t + (1/2)·a·t²

Δs = Distance = 100-m - 80-m = 20-m

u = The initial velocity of Jenny = 0

a = Jenny's acceleration = 1.0 m/s²

∴ 20 = 0×t + (1/2) × 1 × t² = t²/2

20 = t²/2

t = √(20 × 2) = 2·√10

The time it takes Jenny to run from the 80-m mark to the 100-m mark = 2·√10 seconds

b) The distance Linda runs in t = 2·√10 seconds, d = v × t

Given that Linda's velocity, v = 8.6 m/s, we have;

d = 8.0 × 2·√10 = 16·√10

The distance Linda runs in t = 2·√10 seconds = 16·√10 meters ≈ 50.6 meters

Therefore, Linda should be approximately (50.6 - 20) meters = 30.6 meters behind Jenny when Jenny starts running

c) Jenny's speed at the 100 m mark is given as follows;

v = u + a·t

t = 2·√10 seconds, a = 1.0 m/s², u = 0

∴ v = 0×t + 1.0×2·√10 = 2·√10 ≈ 6.325

Jenny's speed at the 100-m mark ≈ 6.325 m/s

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