Answer:
1.48 kg
Explanation:
mass of copper = 4 kg
Decrease in temperature of copper = 36.9°C
increase in temperature of water = 9.20°C
Let the mass of water is m.
Specific heat of water = 4181 J/Kg°C
Specific heat of copper = 385 J/kg°C
According to the principle of caloriemetery
Heat lost by copper = heat gained by water
mass of copper x specific heat of copper x decrease in temperature = mass of water x specific heat of water x increase in temperature
4 x 385 x 36.9 = m x 4181 x 9.20
56826 = 38465.2 m
m = 1.48 kg
Thus, the mas of water is 1.48 kg.
mas of water
Answer:
a.After
second Mr Comer's speed

b.Distance travelled by Mr.Comer in
seconds

Explanation:
a. Lets recall our first equation of motion 
Now we know that
,
and

Plugging the values we have.




Then Mr.Comer's speed after
sec

b.
Lets find the distance and recall our third equation of motion.

So
distance covered.
Dividing both sides with 2a we have.

Plugging the values.


So Mr.Comer will travel a distance of
.
There's no reason that a change in global temperatures should shrink mountains.
The work that need to do is 66.24 J.
<h3>Explanation :</h3>
Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

If :
- W = work (J)
- F = force (N)
- s = shift (m)
- θ = elevation angle (°)
We know that :
- x = the horizontal shift = 9,2 m
- θ = elevation angle = 15°
W = work = ... J

So, the work that need to do is 66.24 J.
<u>Subject</u><u> </u><u>:</u><u> </u><u> </u><u>Physics</u><u> </u>
<u>Class</u><u> </u><u>:</u><u> </u><u>Junior</u><u> </u><u>High</u><u> </u><u>School</u><u>/</u><u>Senior</u><u> </u><u>High</u><u> </u><u>School</u><u> </u>
<u>Keyword</u><u> </u><u>:</u><u> </u><u>Work</u><u>;</u><u> </u><u>Force</u><u>;</u><u> </u><u>Shift</u><u>;</u><u> </u><u>and</u><u> </u><u>Elevation</u><u> </u><u>Angle</u><u> </u>
Power rating = volts x amps
Power rating = 7.5 x 120 = 900 watts
Answer: 900 watts