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barxatty [35]
3 years ago
10

If you expose a photosynthesizing plant to water that contains both radioactive h and radioactive o, in which of the products of

photosynthesis will the radioactive h and o show up? if you expose a photosynthesizing plant to water that contains both radioactive h and radioactive o, in which of the products of photosynthesis will the radioactive h and o show up? h in glucose and water; o in o2 h in glucose; o in water h in water; o in glucose h and o both in glucose
Chemistry
1 answer:
ValentinkaMS [17]3 years ago
3 0
I think the answer is H in glucose and water and O in O2. Photosynthesis is the process in which green plants and other organism convert light energy to chemical energy which is used in activities within the organism. Water that is exposed to the plant reacts with carbon dioxide to produce sugar and oxygen. The radioactive O will hence show up in the oxygen molecule and the radioactive H shows up in the sugar/ glucose molecule.
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6th grade help me pleaseeeee
Vesnalui [34]

Answer:

the answer would be A. cells

Explanation:

just trust me Im a 8th grader and I did that before

7 0
3 years ago
What is the percent composition by mass of sulfur in the compound mgso4
Margaret [11]

Answer:

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.

Explanation:

Molar mass of compound = 120 g/mol

Number of sulfur atom = 1

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

=\frac{\text{Number of atoms}\times \text{Atomic mass}}{\text{molar mas of compound}}\times 100

Sulfur :

=\frac{1\times 32 g/mol}{120 g/mol}\times 100=26.7\%

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.

6 0
3 years ago
What type of bonds are these?
gulaghasi [49]
Jeez this is middle school really. covalently bond
3 0
3 years ago
In the disproportionation reaction CI2 + H2Omc021-1.jpgHCIO + HCI, what describes the oxidation states of the substance Cl?
Sophie [7]
<span>Reaction: CI2 + H2O    ---->  HCIO + HCI

Oxidations states:

The oxitation state of Cl2 = 0, because the oxidation state of an atom alone or a molucule with one kind of atom is always 0.

The oxidation state of Cl in HClO is +1 because the oxidation state of H is + 1, the oxidation state of O is - 2, and the molecule is neutral, so  +1 + 1 - 2 = 0

The oxidation state of Cl in HCl is - 1, because the oxidation state of H is +1 and the molecule is neutral, so - 1 + 1 = 0.

Also, you shall remember that when an atom increases its oxidation state is is oxidized and when an atoms reduces its oxidations state it is reduced.

With that you conclude that the right option is the last statement: </span>Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation number +1 in HClO.
8 0
4 years ago
At a certain temperature, the solubility of strontium arsenate, Sr3(AsO4)2, is 0.0540 g/L. What is the Ksp of this salt at this
blondinia [14]
 <span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles 

Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq) 

Ksp = (Sr++)^3(As04^-3)^2 

(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4 

(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4 

<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th


I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span></span>
7 0
3 years ago
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