Answer:
184620169 g.
We can say that this mass corresponds to 184.6 ton
Explanation:
This is the reaction: 2Mg (s) + O₂(g) → 2MgO (s)
We have the data of O₂, so let's find out the moles with the Ideal Gases Law.
First of all, we convert pressure to atm
760 Torr / 3.4×10⁻⁶ Torr = 223529.4 atm
P .V = n . R . T
223529.4 atm . 0.432L = n . 0.082 L.atm/mol.K . 301K
(223529.4 atm . 0.432L) / (0.082 L.atm/mol.K . 301K) = 3798769 moles
Gosh!, These are a lot of moles.
Ratio is 1:2. So with 3798769 moles we would need the double of moles of Mg. → 3798769 mol .2 = 7597538 moles
Let's convert this moles into mass ( mol . molar mass)
7597538 mol . 24.3 g/mol = 184620169 g
We can convert this mass to ton
1 ton = 1×10⁶ g
184620169 g / 1×10⁶ g = 184.6 ton
