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3 years ago

What hormone is not related to stress

Physics

1 answer:

viktelen [127]3 years ago

8 0

The answer would be Estrogen, because that is a female sex hormone

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Find the kenetic energy of a car of mass 700kg racing with a velocity of 10m/s

fiasKO [112]

Answer:

35000 KJ

Explanation:

The equation for the kinetic energy is given by the formula :

$E_{k} = \frac{1}{2} mv^{2}$

$E_{k} = \frac{1}{2} (700)(10)^{2}$

$E_{k} = \frac{1}{2} (700)(100)$

$E_{k} = (350)(100)$ OR $E_{k} = \frac{1}{2} (70000)$

$E_{k} = 35000$

Units will be kilojoules since the units of mass was kilograms .

Our final answer is 35000 KJ

Hope this helped and have a good day

5 0

1 year ago

A block slides down a frictionless plane having an inclination of 15.0°. The block starts from rest at the top, and the length o

nalin [4]

Answer: check the pic

Explanation:

8 0

2 years ago

Plz help me asap !!!!!!!!!!

nlexa [21]

Answer:

B- 65km

C- 2.8km/h

D- average speed

6 0

3 years ago

How much thermal energy is created in the slope and the tube during the ascent of a 30-m-high, 120-m-long slope?

charle [14.2K]

The change in internal energy is only gravitional PE because the tube is being drug up at a constant speed. Since it is at a constant speed, the change in KE is 0. Change in PE = m*g*h = 78 kg * 10 m/s^2 * 30 m = 23400 J Work done on the system is from the force Work = force * distance = 350 N * 120 m = 42000 J So, work added 42000 J to the system, but the rider's energy only increased 23400 J. Therefore, friction took up the difference. Friction is where the thermal energy comes from Q = 42000 J - 23400 J = 18600 J. Therfore, friction generated 18600 J of heat to the surroundings.

7 0

3 years ago

A 12,000kg. railroad car is traveling at +2m/s when it

ivann1987 [24]

Answer:

The final velocity of the two railroad cars is 1.09 m/s

Explanation:

Since we are given that the two cars lock together it shows that the collision is inelastic in nature. The final velocity due to inelastic collision is given by

$\mathrm{V}=\frac{V 1 M 1+V 2 M 2}{M 1+M 2}$

where

V= Final velocity

M1= mass of the first object in kgs = 12000

M2= mas of the second object in kgs = 10000

V1= initial velocity of the first object in m/s = 2m/s

V2= initial velocity of the second object in m/s = 0 (given at rest)

Substituting the given values in the formula we get

V = 2×12000 + 0x100012000 + 10000= 2400022000= 1.09 m/s

$\mathrm{V}=\frac{2 \times 1200+0 \times 1000}{12000+10000}=\frac{24000}{22000}=1.09 \mathrm{m} / \mathrm{s}$

Which is the final velocity of the two railroad cars

8 0

3 years ago