1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fgiga [73]
3 years ago
11

Why should the substage condenser not be included in computing the magnification?

Physics
2 answers:
Leni [432]3 years ago
5 0
The reason as to why the substage condenser does not need to be included in computing the magnification and the only component needed is the ocular lens and the objective lenses is because the condenser is only responsible for gathering light and it does not contribute with the magnification of the object under the microscope.
Fantom [35]3 years ago
3 0

Answer:

It does not affect the magnification

Explanation:

The substage condenser does not affect the total magnification.

The function of the condenser is to focus the light that will enter the lenses.

The light has to be condensed, otherwise if it is unfocused, it will be a lot more difficult to view the object placed on the stage of the microscope.

You might be interested in
The gravitational force between two objects is f. If masses of both objects are halved without changing distance between them, t
Marrrta [24]

The gravitation force is quartered when two objects' masses are halved without changing their distance.

Gravitational law states that the force of attraction and repulsion between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

F=(KM1 M2)/r^2

K= Gravitation force constant

M1M2 = masses of the object

r = distance between objects

When M1 and M2 are halved, it becomes M1/2 and M2/2

F=(K M1/2 x M2/2)/r^2

F=(K (M1 x M2)/4)/r^2

F=(KM1 x M2)/(4r^2 )

Recall

F=(KM1 x M2)/r^2

Therefore

F=F/4

Learn more about gravitational force here:

brainly.com/question/25408095

#SPJ4

7 0
2 years ago
F= (9.3 x 105 )(4.2 x 10-15)
kvv77 [185]

Answer:

3.906E-9 or 3.906 x 10-9

Explanation:

8 0
3 years ago
A stone is dropped from the upper observation deck of a tower, "500" m above the ground. (Assume g = 9.8 m/s2.) (a) Find the dis
Yuri [45]

Answer:

h₍₁₎ = 495,1 meters

h₍₂₎ = 480,4 m

h₍₃₎ = 455,9 m

...

..

Explanation:

The exercise is "free fall". t = \sqrt{\frac{2h}{g} }

Solving with this formula you find the time it takes for the stone to reach the ground (T) = 102,04 s

The heights (h) according to his time (t) are found according to the formula:

h(t) = 500 - 1/2 * g * t²

Remplacing "t" with the desired time.

4 0
3 years ago
There is a current of 0.83 A through a lightbulb in a 120 V circuit. What is the resistance of this lightbulb?
Lemur [1.5K]

Considering the Ohm's law, the resistance of the lightbulb is 144.58 Ω.

<h3>Definition of current</h3>

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

<h3>Definition of voltage</h3>

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

<h3>Definition of resistance</h3>

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

<h3>Ohm's law</h3>

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

I=\frac{V}{R}

Where:

  • I is the current measured in amps (A).
  • V the voltage measured in volts (V).
  • R the resistance that is measured in ohms (Ω).

<h3>Resistance of the lightbulb</h3>

In this case, you know that the voltage between two points in a circuit is 120 V and there is a current of 0.83 A.

Replacing in the Ohm's Law:

0.83A=\frac{120 V}{R}

Solving:

0.83 A× R=  120 V

R=\frac{120 V}{0.83A}

<u><em>R= 144.58 Ω</em></u>

Finally, the resistance of the lightbulb is 144.58 Ω.

Learn more about Ohm's law:

brainly.com/question/13076023

brainly.com/question/17286882

brainly.com/question/2275770

#SPJ1

3 0
2 years ago
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
eduard
Uhh? Do you have any questions or need help?
7 0
3 years ago
Read 2 more answers
Other questions:
  • Which waves cause the medium to vibrate only in a direction parrallel?
    15·2 answers
  • What happens to matter when we add or take away heat energy?
    15·1 answer
  • Me kitten runs 40 meters in 8 seconds what is his speed?
    8·2 answers
  • Choose the answers that describe an example of acceleration.
    7·1 answer
  • 2 Points<br> When must scientific theories be changed?
    8·1 answer
  • Two children push on heavy crate that rests on a basement floor. one pushes horizontally with a force of 150 N and the other pus
    9·1 answer
  • Why do people eat vegetables? Not just to stay healthy!!! But why else do we eat and need vegetables?
    7·1 answer
  • Can an object emit different portions of the electromagnetic spectrum at the same time?
    15·1 answer
  • What principle do Tesla coils use to generate electricity?
    15·1 answer
  • If the mass of an ideal pendulum is doubled how will the oscillation period change?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!