All categories

2 years ago

What is the difference between creep and a landslide

Physics

2 answers:

dolphi86 [110]2 years ago

5 0

Creep creeps up lanslide comes down fast

Tomtit [17]2 years ago

5 0

Creep is the slow downward flow of rock and soil down a low grade slope.A landslide is the movement of rocks or debris down a sloped section of land.

You might be interested in

Why has the model of the atom changed over time?

Makovka662 [10]

<span>A.
The model of the atom evolved as scientists have made new discoveries.</span>

7 0

2 years ago

What impulse occurs when an average force of 7.0 N is exerted on a cart for 2.5 s ?

makkiz [27]

Answer: $1.7\times 10$

Explanation:

Given

Force $F=7 N$

time interval $t=2.5 s$

Impulse is given by $=Force \times time\ interval\ for\ applied\ force$

$Impulse=7\times 2.5=17.5$

For two significant Figure

$Impulse=1.7\times 10$

7 0

3 years ago

You walk 12.0 m West and then 4.00 m south. What is your displacement?

Karo-lina-s [1.5K]

Answer:

12.6 (3 sig. fig.)

Explanation:

(12^2 + 4^2)^1/2 = 12.6 (3 sig. fig.)

7 0

2 years ago

Which of the following is most likely to be an observation made by a physiologist

Naya [18.7K]

Do you have the answer choices ?

3 0

3 years ago

An electric dipole is formed from ±1.00nC charges spaced 3.00 mm apart. The dipole is at the origin, oriented along the x-axis.

Ronch [10]

Answer:

Value of electric field along the axis and equitorial axis $E=31.25\ N/c$ and $E = 15.625\ N/c$ respectively.

Explanation:

Given :

Distance between charges , $d = 3 \ mm =\dfrac{3}{1000}\ m=3\times 10^{-3}\ m.$

Magnitude of charges , $q=1\ nC = 10^{-9}\ C.$

Dipole moment , $p=qL=10^{-9}\times 3\times 10^{-3}=3\times 10^{-12} \ C\ m.$

Case A) (x,y) = (12.0 cm, 0 cm) :

Electric field of dipole in its axis ,

$E=\dfrac{2kp}{r^3}$

Putting all values and $r=12\times 10^{-2}\ m.$

We get , $E=31.25\ N/c.$

Case B) (x,y) = (0 cm, 12.0 cm) :

Electric field of dipole on equitorial axis ,

$E = \dfrac{kp}{r^3}$

Putting all values and $r=12\times 10^{-2}\ m.$

We get , $E = 15.625\ N/c.$

Hence , this is the required solution.

7 0

3 years ago