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vichka [17]
3 years ago
12

A 150 kg safe on frictionless casters is being raised at 1.20m to the bed of a truck using planks 4m long. The force needed to p

ush the safe up is
Physics
1 answer:
Vesnalui [34]3 years ago
3 0
The only thing you need to know in order to solve this task is that <span>plank length (which is force x), should equal the increase in potential energy, so what we have now : (mass)* g * (height).
It has to look like that:  </span>
<span>F * 3.0 = 150 x 9.81 x 1.20 
Then solve for F, the result should be in newtones = 588N

Do hope it makes sense.</span>
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Sand falls from a conveyor belt at a rate of 30 m3m3/min onto the top of a conical pile. The height of the pile is always 3535 o
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Explanation:

As the given data is as follows.

         h = \frac{3}{5}d

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and       Volume (V) = \frac{1}{3} \pir^{2}h

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                         = \frac{16}{27} \pi h^{3}

And,  \frac{dV}{dt} = \frac{3 \times 16}{27} \pi h^{2} \frac{dh}{dt}

         \frac{dV}{dt} = \frac{16}{9} \pi h^{2} \frac{dh}{dt}

Putting the given values into the above formula as follows.

       \frac{dV}{dt} = \frac{16}{9} \pi h^{2} \frac{dh}{dt}

       30 m^{3}/min = \frac{16}{9} \pi (2)^{2} \frac{dh}{dt}    

          [tex]\frac{dh}{dt} = 1.343 m/min

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