Answer:
50°
Explanation:
It is given that the both scales are the same at 18˚
Now,
at 30˚ on the Cantor scale, the temperature is 30˚ − 18˚ = 12˚ above
the 18˚ mark.
also, it is given that with every 3˚ increase in the temperature on the Cantor scale is there is an 8˚ increase on the Frobenius scale,
mathematically, we can write it as (by unitary method)
3˚ increase in the temperature on the Cantor = 8˚ increase on the Frobenius scale
or
1˚ increase in the temperature on the Cantor = (8/3)˚ increase on the Frobenius scale
thus, for x˚ increase in the temperature on the Cantor = ((8/3)˚ × x) increase on the Frobenius scale
hence, for 12° increase we have
12˚ increase in the temperature on the Cantor = ((8/3)˚ × 12) increase on the Frobenius scale
or
12˚ increase in the temperature on the Cantor = 32° increase on the Frobenius scale
hence, the final reading on the Frobenius scale will be, 18˚ + 32˚ = 50˚.