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Digiron [165]
3 years ago
12

If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you

pull with 250 N so the desk slides at constant velocity, the friction force is
Physics
1 answer:
s344n2d4d5 [400]3 years ago
8 0

Answer:

The friction force is 250 N

Explanation:

The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):

\sum F=ma

In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:

\sum F = 0 (1)

We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:

- the pull, forward, F = 250 N

- the friction force, backward, F_f

Given (1), we have

F-F_f = 0

So the force of friction must be equal to the pull:

F=F_f = 250 N

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Explanation:

1 inch = 25.4 mm

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Since, 1 foot = 12 inches

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0.5 m/s².

Explanation:

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Initial velocity (u) = 0 m/s

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Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

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a is the acceleration.

v is the final velocity.

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t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

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Time (t) = 20 s

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a = (10 – 0) / 20

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a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

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