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Goryan [66]
3 years ago
5

Suppose Person A runs off the edge of the cliff at 2 m/s and Person B runs off the edge at 1 m/s. Which will hit the ground fart

her from the base of the cliff?
Physics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

<h2>Person A will hit a distance father</h2>

Explanation:

Based on the fact that the velocity of person A is more than that of person B, that is from the question, person A has a velocity of 2m/s and person B has a velocity of 1m/s, this clearly shows that person A has the tendency to hit a distance farther from the cliff than person B.

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Find the y-component of this
Alborosie

Answer:

-0.0789 m

Explanation:

Recall that the y-component comes associated with the sin(18.4) through the following trigonometric relationship:

y = 0.250 sin(-18.4) ≈ -0.0789 m

Notice it is negative since it is below the x-axis.

4 0
3 years ago
What is the law of conservation of energy.
Sever21 [200]

The law of conservation of energy implies that energy can neither be created nor destroyed, but can be changed from one form to another.

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2 years ago
Car À moves at a speed of 8m/s for 43 seconds. Car B moves at a speed of 7 m/s for 50 seconds. Which car traveled a longer dista
nadezda [96]

Distance = (speed) x (time)

Car A: Distance = (8 m/s) x (43 s)  =  344 meters

Car B: Distance = (7 m/s) x (50 s)  =  350 meters

350 meters is a longer distance than 344 meters.

<em>Car-B traveled a longer distance</em> than Car-A did.

5 0
2 years ago
Read 2 more answers
Two charges, qA and qB, are separated by a distance, d, and exert a force, F, on each other. Analyze Coulomb's law and answer th
maria [59]

Answer: a. F doubled

b. F reduced by one-quarter i.e

1/4*(F)

c. 1/9*(F)

d. F increased by a factor of 4 i.e 4*F

e. F reduces 3/4*(F)

Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is

F = k*(qA*qB)/d²

a. If qA is doubled therefore the force is doubled since they are directly proportional.

b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4

Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.

c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9

d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4

e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,

3/4*F

6 0
3 years ago
You should increase the distance between your car and the vehicle ahead when you:
ELEN [110]
<span>You should increase the distance between your car and the vehicle ahead when you are being tailgated by another driver.
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8 0
3 years ago
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