Answer:
Explanation:
In the first attached image, we can see, the nomenclature used for Angle orientations.
To sum the vectors we must join the head of one of them with the tail of the next, at the end joins the tail of the first vector with the head of the last vector.
In the second attached image, we can find graphically the sum of each of the vectors.
The resultant vector has a length of 57.36[m], and goes 48° north of east.
Answer:
Bind it to a large protein
Explanation:
An antigen is a molecule that binds to Ag-specific receptors, but cannot necessarily induce an immune response in the body by itself. Antigens are proteins , peptides (amino acid chains) and
polysaccharides (chains of monosaccharides/simple sugars) but
lipids and nucleic acids become antigens only when combined with proteins and polysaccharides. [4] In general, saccharides and lipids (as opposed to peptides) qualify as antigens but not as immunogens since they cannot elicit an immune response on their own. Furthermore, for a peptide to induce an immune response it must be a large enough size, thus binding to proteins
<span>Answer:
Correct answer is
just add the two kinetic energies;
E = (1/2)mv^2 + (1/2)mv^2</span>
To develop this problem we will apply the concepts related to the kinematic equations of motion, specifically that of acceleration. Acceleration can be defined as the change of speed in an instant of time, mathematically this is
![\vec{a} = \frac{\vec{v_2}-\vec{v_1}}{\Delta t}](https://tex.z-dn.net/?f=%5Cvec%7Ba%7D%20%3D%20%5Cfrac%7B%5Cvec%7Bv_2%7D-%5Cvec%7Bv_1%7D%7D%7B%5CDelta%20t%7D)
If a mobile is decreasing its speed (it is slowing down), then its acceleration is in the opposite direction to the movement. This would imply that the acceleration vector is opposite to the velocity vector.
Therefore the correct answer is B.
Answer:
Explanation:
24 - gauge wire , diameter = .51 mm .
Resistivity of copper ρ = 1.72 x 10⁻⁸ ohm-m
R = ρ l / s
1.72x 10⁻⁸ / [3.14 x( .51/2)² x 10⁻⁶ ]
= 8.42 x 10⁻² ohm
= .084 ohm
B ) Current required through this wire
= 12 / .084 A
= 142.85 A
C )
Let required length be l
resistance = .084 l
2 = 12 / .084 l
l = 12 / (2 x .084)
= 71.42 m