Answer:
3
Explanation:
half life, T = 12 million years
total life, t = 36 million years
Let n be the number of half lives.
n = Total life / half life
n = 36 / 12 = 3
So, the number of half lives are 3.
Answer:
Velocity = 15.87m/s
Explanation:
Given the following data;
Distance, d = 200000m
Time, t = 12600secs
*To find the velocity*
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
Substituting into the equation, we have;
Velocity = 15.87m/s
<em>Therefore, the velocity of the car is 15.87 meters per seconds due west.</em>
Answer:
a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.
b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.
Explanation:
a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:
Jet
(1)
Glider
(2)
Where:
- Thrust of jet engines, measured in newtons.
- Tension in the cable connecting the jet and glider, measured in newtons.
, - Masses of the glider and the jet, measured in kilograms.
- Acceleration of the glider-jet system, measured in meters per square second.
If we know that , and , then the solution of this system of equations:
By (2):
By (1):
The magnitude of the thrust provided by the jet's engines is 4840 newtons.
b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.
Answer:
the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake
Explanation:
This problem can be solved using the kinematics relations, let's start by finding the final velocity of the acceleration period
v² = v₀² + 2 a₁ x
indicate that the initial velocity is zero
v² = 2 a₁ x
let's calculate
v =
v = 143.666 m / s
now for the second interval let's find the distance it takes to stop
v₂² = v² - 2 a₂ x₂
in this part the final velocity is zero (v₂ = 0)
0 = v² - 2 a₂ x₂
x₂ = v² / 2a₂
let's calculate
x₂ =
x₂ = 573 m
as the stopping distance is greater than the free length of the track, the vehicle leaves the track before it can brake
Answer:
The smallest and largest areas could be 6400 m and 7500 m, respectively.
Explanation:
The area of a rectangle is given by:
Where:
l: is the length = 100 m
w: is the width
We can calculate the smallest area with the lower value of the width.
And the largest area is:
Therefore, the smallest and largest areas could be 6400 m and 7500 m, respectively.
I hope it helps you!