Answer:
The tasks A and B will be performed together, then C, D and E will be performed one by one and then F and G will be performed to enable the final task H which will be performed last.
Total task time is 49 mins
= 4 + 7 + 6 + 5 + 6 + 7 + 8 + 6
=49 mins.
Cycle time is 10 min per chair
Production time available per day divided by units required per day
480 minutes / 50 chairs
= 10 mins per chair.
Minimum number of workstation
49 mins / 10 mins = 5 workstations
Explanation:
The tasks A and B will be performed together, then C, D and E will be performed one by one and then F and G will be performed to enable the final task H which will be performed last.
Total task time is 49 mins
= 4 + 7 + 6 + 5 + 6 + 7 + 8 + 6
=49 mins.
Cycle time is 10 min per chair
Production time available per day divided by units required per day
480 minutes / 50 chairs
= 10 mins per chair.
Minimum number of workstation
49 mins / 10 mins = 5 workstations
