Ask question

Ask question

All categories

3 years ago

9

How to find equation hyperbola with asymptotes, center and transverse?

1 answer:

lapo4ka [179]3 years ago

6 0

The equation for a hyperbola is (x-h)/a - (y-k)/b = 1
Or (y-k)/a - (x-h)/b = 1
h represents the x value of the coordinate
k value represents the y value of the coordinate
together they represent a point, which is the center
So (h,k) is (x,y)

The asymptote is y-k = +/- b/a (x-h)
The transverse is the line that goes through the hyperbola.

You might be interested in

In triangle ABC, angleACB is a right angle

viktelen [127]

Answer:

I think is 11.4

.........

6 0

3 years ago

Please help stepbrother or gayvibes <br> also pls ignore that i chose one of the answers

lubasha [3.4K]

Answer:

it's the last one on the bottom (the one you chose)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

If 18 793is multiplied by 1000 then what is the product

Yakvenalex [24]

Answer:

18793000

Step-by-step explanation:

5 0

2 years ago

Can someone answer and show me how you answered both of these equations.(it’s simple division)

valina [46]

Answer:

first is 9.08

second is 17.34

6 0

3 years ago

The length (in centimeters) of a typical Pacific halibut t years old is approximately f(t) = 200(1 − 0.956e−0.18t). Suppose a Pa

horsena [70]

Answer:

7.2 years

Step-by-step explanation:

$f(t) =200(1 - 0.956e^{-0.18t})$

where f(t) is the length and t is the number of years old

given the Mike measures 148 cm, we need to find out the age

So we plug in 148 for f(t) and solve for t

$148 =200(1 - 0.956e^{-0.18t})$

divide both sides by 200

$\frac{148}{200} = 1 - 0.956e^{-0.18t}$

Now subtract 1 from both sides

$-0.26= - 0.956e^{-0.18t}$

Divide both sides by -0.956

$\frac{0.26}{0.956} =e^{-0.18t}$

Now take ln on both sides

$\frac{0.26}{0.956} =e^{-0.18t}$

$ln(\frac{0.26}{0.956} )=-0.18tln(e)$

$ln(\frac{0.26}{0.956} )=-0.18t$

divide both sides by -0.18

t=7.2

So 7.2 years

5 0

3 years ago