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4 years ago

Please find the factors to this equation

Mathematics

1 answer:

Nata [24]4 years ago

5 0

Answer:(x,-14) (x+6)

Step-by-step explanation:

I think correct me if I am wrong.

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JK=2X KL=X+2 and JK=5X-10

elixir [45]

JK + KL = JL

JK = 2x, KL = x + 2, JL = 5x - 10

therefore we heve the equation:

2x + (x + 2) = 5x - 10

3x + 2 = 5x - 10 |-2

3x = 5x - 12 |-5x

-2x = -12 |:(-2)

x = 6

JK = 2x → JK = 2(6) = 12

KL = x + 2 → KL = 6 + 2 = 8

JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20

Check:

JK + KL = JL

12 + 8 = 20 CORRECT :)

5 0

4 years ago

For Home Economics class, Sandra has 5 cups of flour. She made 3 batches of cookies that each used 1.5 cups of flour. Write and

Lemur [1.5K]

Sandra has .5 of flour left after making 3 batches of cookies

6 0

3 years ago

A regular octagon has a radius of 6 ft and a side length of

Svetlanka [38]

Answer:

<h2>Area of the regular octagon is approximately 102ft²</h2>

Step-by-step explanation:

Given the radius and length of a side of regular octagon as shown;

radius = 6ft and length of side = 4.6ft

Area of a regular octagon is expressed as $A = 2(1+\sqrt{2} )a^{2}$ where a is the length of one side. Given a = 4.6ft

Area = $A = 2(1+\sqrt{2} )(4.6)^{2}\\$

$= 2(1+\sqrt{2} )*21.16\\= (2+2\sqrt{2})*21.16\\ = 4.83*21.16\\= 102.20ft^{2} \\$

Area of the regular octagon is approximately 102ft²

3 0

3 years ago

Sandy's car can travel 42 miles on 1 1/6 gallons of gas. At that rate, how many miles per gallon does her car get?

V125BC [204]

We simply have to divide the total miles that the car can travel by the total amount of gallons of gas.
So,
42 miles/ (11/6 gallons) = 22.91 miles per gallon

Therefore, Sandy's car gets 22.91 miles per gallon of gas

4 0

3 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago