JK + KL = JL
JK = 2x, KL = x + 2, JL = 5x - 10
therefore we heve the equation:
2x + (x + 2) = 5x - 10
3x + 2 = 5x - 10 |-2
3x = 5x - 12 |-5x
-2x = -12 |:(-2)
x = 6
JK = 2x → JK = 2(6) = 12
KL = x + 2 → KL = 6 + 2 = 8
JL = 5x - 10 → JL = 5(6) - 10 = 30 - 10 = 20
Check:
JK + KL = JL
12 + 8 = 20 CORRECT :)
Sandra has .5 of flour left after making 3 batches of cookies
Answer:
<h2>
Area of the regular octagon is approximately 102ft²</h2>
Step-by-step explanation:
Given the radius and length of a side of regular octagon as shown;
radius = 6ft and length of side = 4.6ft
Area of a regular octagon is expressed as
where a is the length of one side. Given a = 4.6ft
Area = 

Area of the regular octagon is approximately 102ft²
We simply have to divide the total miles that the car can travel by the total amount of gallons of gas.
So,
42 miles/ (11/6 gallons) = 22.91 miles per gallon
Therefore, Sandy's car gets 22.91 miles per gallon of gas

- Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>
- To find - <u>Area </u><u>of </u><u>trapezium</u>
Refer the figure attached ~
In the given figure ,
AB = 25 cm
BC = AD = 15 cm
CD = 13 cm
<u>Construction</u><u> </u><u>-</u>

Now , we can clearly see that AECD is a parallelogram !
AE = CD = 13 cm
Now ,

Now , In ∆ BCE ,

Now , by Heron's formula

Also ,

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

hope helpful :D