We subtract the enthalpies of the reactants from that of the products:

Since this is < 0, this is an exothermic reaction.
First convert the kg to g ----- 0.03kg = 30g
Then divide the mass by the volume ----- 30g ÷ 25mL = 1.2
The density is 1.2g/mL<span />
The mixture flow rate in lbm/h = 117.65 lbm/h
<h3>Further explanation</h3>
Given
15.0 wt% methanol
The flow rate of the methyl acetate :100 lbm/h
Required
the mixture flow rate in lbm/h
Solution
mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.
1 kg mixture = 0.85 .methyl acetate
So flow rate for mixture :

Volume of a substance can be determined by dividing mass of the substance by its density.
That can be mathematical shown as:
Density=Mass/Volume
So, Volume=Mass/Density
Here mass of the substance given as 24.60 g
Whereas density of the substance is 2.70 g/mL
So,
Volume=Mass/Density
=24.6/2.7
=9.1 mL
So volume of the substance is 9.1 mL.
Answer:
the first thing you do is do your experiment then title it. then state the purpose of the experiment. included a summary of the experiment. make a list of the materials you used. present all the steps in order to make the experiment possible. note any changes to the original procedure. this is basically the steps you have to do in order to make your scientific experiment.