Answer:
2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2
Explanation:
Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2
Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.
Not all acid-catalyzed conversions of alcohols to alkyl halides proceed through the formation of carbocations. Primary alcohols and methanol react to form alkyl halides under acidic conditions by an SN2 mechanism.
Not all acid-catalyzed conversions of alcohols to alkyl halides proceed through the formation of carbocations. Primary alcohols and methanol react to form alkyl halides under acidic conditions by an SN2 mechanism.
In these reactions the function of the acid is to produce a protonated alcohol. The halide ion then displaces a molecule of water (a good leaving group) from carbon; this produces an alkyl halide:
Again, acid is required. Although halide ions (particularly iodide and bromide ions) are strong nucleophiles, they are not strong enough to carry out substitution reactions with alcohols themselves. Direct displacement of the hydroxyl group does not occur because the leaving group would have to be a strongly basic hydroxide ion:
We can see now why the reactions of alcohols with hydrogen halides are acid-promoted.
Carbocation rearrangements are extremely common in organic chemistry reactions are are defined as the movement of a carbocation from an unstable state to a more stable state through the use of various structural reorganizational "shifts" within the molecule. Once the carbocation has shifted over to a different carbon, we can say that there is a structural isomer of the initial molecule. However, this phenomenon is not as simple as it sounds.
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This number in scientific notation is 5.089(10^6).
Answer:
The density of liquid is 3 g/mL.
The mass of liquid is 60 g.
The volume of liquid is 10 mL.
Explanation:
Given data:
Density of liquid = ?
Mass of liquid = 30 g
Volume of liquid = 10 mL
Solution:
d = m/v
d = density
m = mass
v = volume
Now we will put the values in formula.
d = 30 g/ 10 mL
d = 3 g/mL
The density of liquid is 3 g/mL.
2nd:
Given data:
Density of liquid = 2 g/mL
Volume of liquid = 30 mL
Mass of liquid = ?
Solution:
d = m/v
2 g/mL = m/ 30 mL
m = 2 g/mL×30 mL
m = 60 g
The mass of liquid is 60 g.
3rd:
Given data:
Density of liquid = 5 g/mL
Mass of liquid = 50 g
Volume of liquid = ?
Solution:
d = m/v
5 g/mL = 50 g/ v
v = 50 g/5 g/mL
v = 10 mL
The volume of liquid is 10 mL.
The tubes 1, 5 and 6 is the answer to the question which test tubes were used to determine the optimal ph lipase activity. Lipase is an enzyme and optimum ph the maximum possible point on which enzyme become active.
