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VARVARA [1.3K]
4 years ago
5

How would a solution that is labeled 5.0 M would be read as?

Chemistry
2 answers:
Ivanshal [37]4 years ago
8 0
5 moles because molarity signifies number of moles dissolved in One litre of water
Pie4 years ago
7 0

Answer: Option (a) is the correct answer.

Explanation:

It is known that molarity is the number of moles of a substance present in liter of a solution.

Mathematically,    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

Symbol which represents molarity is "M". For example, a solution of 5.0 M means that molarity of the solution is 5.0 or the solution is 5.0 molar.

Thus, we can conclude that a solution that is labeled 5.0 M would be read as 5.0 molar.

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A reaction has a rate constant of 2.08 × 10−4 s−1 at 26 oC and 0.394 s−1 at 79 oC . Determine the activation barrier for the rea
leva [86]

<u>Answer:</u> The activation energy of the reaction is 124.6 kJ/mol

<u>Explanation:</u>

To calculate activation energy of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{79^oC}}{K_{26^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{79^oC} = equilibrium constant at 79°C = 0.394s^{-1}

K_{26^oC} = equilibrium constant at 26°C = 2.08\times 10^{-4}s^{-1}

E_a = Activation energy of the reaction = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 26^oC=[26+273]K=299K

T_2 = final temperature = 79^oC=[79+273]K=352K

Putting values in above equation, we get:

\ln(\frac{0.394}{2.08\times 10^{-4}})=\frac{E_a}{8.314J/mol.K}[\frac{1}{299}-\frac{1}{352}]\\\\E_a=124595J/mol=124.6kJ/mol

Hence, the activation energy of the reaction is 124.6 kJ/mol

3 0
3 years ago
Which of the following might be in for a rough orbit around the Sun because of debris in their paths? (Choose all that apply.)
GuDViN [60]

Answer:

cerus neptune and eris

Explanation:

6 0
3 years ago
The poison dart from the jungle can kill its prey with a slim from its skin. this is an example of a
nikdorinn [45]
This is an example of a chemical property.
8 0
4 years ago
Aluminum and cloride undergoes a synthesis reaction if 8molnof Al reacts with 10mol of cl, what is the maximum amount of AlCl3 c
Inessa [10]

<u>Answer:</u> The mass of AlCl_3 produced is 889.38 g

<u>Explanation:</u>

We are given:

Moles of Al = 8 mol

Moles of Cl_2 = 10 mol

For the given chemical reaction:

2Al+3Cl_2\rightarrow 2AlCl_3

By stoichiometry of the reaction:

If 3 moles of chlorine gas reacts with 2 moles of Al

So, 10 moles of chlorine gas will react with = \frac{2}{3}\times 10=6.67mol of Al

As the given amount of Al is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, chlorine gas is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 3 moles of Cl_2 produces 2 mole of AlCl_3

So, 10 moles of Cl_2 will produce = \frac{2}{3}\times 10=6.67mol of AlCl_3

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We know, molar mass of AlCl_3 = 133.34 g/mol

Putting values in above equation, we get:

\text{Mass of }AlCl_3=(6.67mol\times 133.34g/mol)=889.38g

Hence, the mass of AlCl_3 produced is 889.38 g

4 0
3 years ago
Brainless if correct
LuckyWell [14K]

Answer:

B

Explanation:

5 0
3 years ago
Read 2 more answers
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