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3 years ago

what’s the slope and y intercept of the loire that is perpendicular to y=-2x-5 and passes through the point (-3,-6)

Mathematics

1 answer:

Doss [256]3 years ago

8 0

Answer:

slope: ½

y-intercept: -4½

Step-by-step explanation:

Slope: negative reciprocal of -2

-1/-2 = 1/2

y = ½x + c

-6 = ½(-3) + c

-6 = -3/2 + c

c = -6 + 3/2

c = -9/2 = -4½

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Select the numbers that make the inquality true. selct all that apply. m > 0

sineoko [7]

Answer:

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Step-by-step explanation:

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3 years ago

Find a:27=6:11, find a

trasher [3.6K]

Answer:

a = 14.73

Step-by-step explanation:

This ratio can also be written like this:

$\frac{a}{27} = \frac{6}{11}$

Then you can cross multiply to get

11a = 6 x 27

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2 years ago

Suppose you have $12,000 to invest. If part is invested at 10% and the rest at 15%, how much should be invested at each rate to

Ivahew [28]

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3 years ago

Which number line can you use to simplify 2 - (-8)?

tigry1 [53]

i would say c is the best answer or the 3rd one

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3 years ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

Urn 1 = 2 red + 4 white = 6 chips
Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : $\frac{1}{3}$ (2 red from 6 chips(2/6=1/2))

For a white one is: $\frac{2}{3}$ (4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

In the first case the probability of taking a white one is of: $\frac{2}{5}$ = 40% ( 2 whites of 5 chips)
In the second case the probability of taking a white one is of: $\frac{1}{5}$ = 20% ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

$\frac{4}{6}$ x $\frac{2}{5}$ = $\frac{4}{15}$ = 26.66% ( $\frac{4}{6}$ the probability of taking a white chip from the urn 1, $\frac{2}{5}$ the probability of taking a white chip from urn two)

For the second case we multiply:

$\frac{1}{3}$ x $\frac{1}{5}$ = $\frac{1}{30}$ = .06% ( $\frac{1}{3}$ the probability of taking a red chip from the urn 1, $\frac{1}{5}$ the probability of taking a white chip from the urn two)

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3 years ago