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velikii [3]
3 years ago
6

The ________________ is the region around the Sun, extending more than one million kilometers from its surface, where the temper

ature can reach two million degrees. This is where the solar winds originate. A) corona B) photosphere C) prominences D) sunspots
Physics
2 answers:
erma4kov [3.2K]3 years ago
8 0
Corona is the right answer
Evgen [1.6K]3 years ago
3 0
This would actually be known to be called the "corona". This would be the <span>the region around the Sun, extending more than one million kilometers from its surface, where the temperature can reach two million degrees. This is where the solar winds originate.

</span><span>The corona is the region around the Sun, extending more than one million kilometers from its surface, where the temperature can reach two million degrees. This is where the solar winds originate.</span>
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A solenoid of 2100 turns, area 10 cm2, and length 30 cm carries a current of 4.0 A. (a) Calculate the magnetic energy stored in
nikitadnepr [17]

Answer:

E = 0.1472  J

Explanation:

Given that,

The number of turns in the solenoid, N = 2100

Area of the solenoid, A = 10 cm² = 0.001 m²

The length of the solenoid, l = 30 cm = 0.3 m

Current in the solenoid, I = 4 A

We need to find the magnetic energy stored in the solenoid. The expression for the stored energy is :

E=\dfrac{1}{2}LI^2

Where

L is self inductance of the solenoid,

L=\dfrac{\mu_oN^2A}{l}\\\\L=\dfrac{4\pi \times 10^{-7}\times 2100^2\times 0.001}{0.3}\\\\L=0.0184\ H

So,

E=\dfrac{1}{2}\times 0.0184\times 4^2\\\\E=0.1472\ J

So, 0.1472  J of energy is stored in the solenoid.

3 0
3 years ago
In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope
zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude g.

If we have the initial velocity v_o and its angle \theta, we can obtain the vertical component of the velocity v_{oy} using trigonometry:

v_{oy}=v_osin\theta

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

Finally, from the equation of horizontal motion with constant speed, we have that:

x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s}  }{9.8\frac{m}{s^{2} } } =7.49m

In words, the projectile travels 7.49m horizontally before it lands.

8 0
4 years ago
You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip take
valkas [14]

Answer: 2 hr 45 min

Explanation:

Given

The average speed between San Diego and Los Angeles is 105\ kmph

time taken for this trip is  1\ hr\ 50\ min\ or\ \frac{11}{6}\ hr

Distance between San Diego and Los Angeles is

\Rightarrow d=105\times \dfrac{11}{6}\\\\\Rightarrow d=192.5\ km

For Friday afternoon, the average speed is  70\ km/h

time taken to complete the trip is

\Rightarrow t=\dfrac{192.5}{70}\\\\\Rightarrow t=2.75\ hr\ or\ 2\ hr\ 45\ min

3 0
3 years ago
Can the velocity of a body revese the direction when acceleration is constant?
andriy [413]

Answer:

Yes, the velocity of the object can reverse direction when its acceleration is constant. For example consider that the velocity of any object at any time t is given as: ... At At t = 0 sec, the magnitude of velocity is 2m/s and is moving in the forward direction i.e.v (t) = -2.

7 0
3 years ago
PLEASE HELP. I NEED THIS FOR TOMMOROW. WILL GIVE BRAINLIEST ​
Fantom [35]

Ansthethethethethe

the is the is

Explanation:

3 0
2 years ago
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